Quantcast
  • Register
PhysicsOverflow is a next-generation academic platform for physicists and astronomers, including a community peer review system and a postgraduate-level discussion forum analogous to MathOverflow.

Welcome to PhysicsOverflow! PhysicsOverflow is an open platform for community peer review and graduate-level Physics discussion.

Please help promote PhysicsOverflow ads elsewhere if you like it.

News

PO is now at the Physics Department of Bielefeld University!

New printer friendly PO pages!

Migration to Bielefeld University was successful!

Please vote for this year's PhysicsOverflow ads!

Please do help out in categorising submissions. Submit a paper to PhysicsOverflow!

... see more

Tools for paper authors

Submit paper
Claim Paper Authorship

Tools for SE users

Search User
Reclaim SE Account
Request Account Merger
Nativise imported posts
Claim post (deleted users)
Import SE post

Users whose questions have been imported from Physics Stack Exchange, Theoretical Physics Stack Exchange, or any other Stack Exchange site are kindly requested to reclaim their account and not to register as a new user.

Public \(\beta\) tools

Report a bug with a feature
Request a new functionality
404 page design
Send feedback

Attributions

(propose a free ad)

Site Statistics

206 submissions , 164 unreviewed
5,103 questions , 2,249 unanswered
5,355 answers , 22,794 comments
1,470 users with positive rep
820 active unimported users
More ...

  Level quantization of 7d $SO(N)$ Chern-Simons action

+ 5 like - 0 dislike
2928 views

In 3d, one can write down the $SO(N)$ Chern-Simons action to be $$S(A)=\frac{k}{192\pi}\int_{M}\text{Tr}(A d A +\frac{2}{3}A^3),$$ where $A$ is an $SO(N)$ connection. The level quantization can be derived as follows:

Let $M^{\prime}$ be a bounding 4-manifold of $M$. We can always find such $M^{\prime}$ since $\Omega^{SO}_3=0$. Extend $A$ to $M^{\prime}$ and define $$S(A)=\frac{k}{192\pi}\int_{M^{\prime}}\text{Tr}(F \wedge F),$$ where $F$ is the curvature 2-form of $A$. We need $\exp(iS_M(A))$ to the independent of the choice of $M^{\prime}$, and the extension of $A$ from $M$ to $M^{\prime}$. Let $M^{\prime\prime}$ be another bounding manifold of $M$, then the difference of $S$ is $$\delta S = \frac{k}{192\pi}\int_{M^{\prime}\cup \bar{M}^{\prime\prime}}\text{Tr}(F \wedge F),$$ where $\bar{M}^{\prime\prime}$ denotes the orientation reversal of $M^{\prime\prime}$. $\delta S$ can be rewritten as $$\delta S = \frac{k\pi}{24}p_1(M^{\prime}\cup \bar{M}^{\prime\prime}) = \frac{k\pi}{8}\sigma(M^{\prime}\cup \bar{M}^{\prime\prime}),$$ where $p_1$ is the first Pontryagin number, and $\sigma$ is the signature of a 4-manifold. We also used the Hirzbruch signature theorem $\sigma(X)=p_1(X)/3$ for 4-manifolds $X$. Since $\sigma(X)$ is an integer, $exp(iS_M(A))$ is well-defined for $k$ equals multiples of 16.

One can use the above argument, together with the fact that $\Omega^{spin}_3=0$ and the Rohlin theorem which implies that the signature of a closed spin 4-manifold is divisible by 16, to argue that for a spin 4-manifold, $\exp(iS)$ is well-defined for $k\in \mathbb{Z}$.

I'm trying to derive the quantization condition of $k$ using similar arguments as above, for 7d $SO(N)$ Chern-Simons action (simply replace $M$ by a 7-manifold, and $A$ by 3-form ). The following facts may be helpful: $\Omega^{SO}_7=0$, $\Omega^{spin}_7=0$, $$\sigma(X) = (7p_2(X)-p_1^2(X))/45$$ for 8-manifold $X$.

This post imported from StackExchange Physics at 2014-09-15 21:05 (UCT), posted by SE-user Zitao Wang
asked Sep 15, 2014 in Theoretical Physics by Zitao Wang (165 points) [ no revision ]

Hi Zitao. I'm confused by your question. In your 3d example, when you write $p_1$ you must mean that $A$ is the metric connection. In 7d, what "metric" 3-form do you have in mind?

Hi Ryan, Thanks for pointing out. I'm being too naive there. The suitable analogous $SO(N)$ Chern-Simons action in 7d should be something like $S=\kappa \text{Tr} (A(dA^3)+\frac{8}{5}A^3(dA)^2+\frac{4}{5}A^2dAAdA+2A^5dA+\frac{4}{7}A^7)$, where $A$ is the metric connection, and I want to determine $\kappa$. The original problem I had in mind is to find a suitable 7d analogue of the 3d gravitational Chern-Simons action that would make the 7d Abelian Chern-Simons action topological. 

Perhaps one can define $A$ as the connection on a principal 3-bundle over some 3-group $G$ as in http://ncatlab.org/nlab/show/7d+Chern-Simons+theory#AbelianTheory for $B^3U(1)$. But I don't know of the 3-group corresponding to $SO(N)$. If this can be done, then we get a differential 3-form, and gravitational Chern-Simons action in its original form makes sense for the 7d case.

I think what you want is some integral characteristic class of the tangent bundle in 8d whose Chern-Weil density is a total derivative. The potential whose differential is the density is the Chern-Simons 7-form. If you look up the original math paper where the Chern-Simons invariant is defined, you can read about the general theory of secondary characteristic classes. Here is the paper http://www.jstor.org/discover/10.2307/1971013?uid=3739560&uid=2&uid=4&uid=3739256&sid=21104636509487

Yes. Using the transgression formula in eq.(3.5) and also eq.(5.13) of your reference, I was able to compute the Chern-Simons 7-form as given in my thread 2 $\frac{1}{2}TP_2(A) =\frac{1}{384\pi^4} \text{Tr} (A(dA^3)+\frac{8}{5}A^3(dA)^2+\frac{4}{5}A^2dAAdA+2A^5dA+\frac{4}{7}A^7)$ where $A$ is an $SO(7)$ connection. So I think the gravitational Chern-Simons action we are looking for in the bosonic case is $S=\int_M\frac{k}{384\pi^4} \text{Tr} (A(dA^3)+\frac{8}{5}A^3(dA)^2+\frac{4}{5}A^2dAAdA+2A^5dA+\frac{4}{7}A^7)$. The quantization of $k$ is a little bit tricky in this case, since $S = \int_{\tilde{M}}\frac{k}{12}(2p_2-p_1^2)$, which is not proportional to the signature of $\tilde{M}$, where $\tilde{M}$ is the bounding 8 manifold of $M$.

But there should be some general results about $p_1$ and $p_2$ for 8-manifolds. Presumably they can be arbitrary integers. Maybe for spin manifolds they have to be divisible by something.

Witten said on page 1 of http://arxiv.org/pdf/hep-th/9609122.pdf that for spin manifolds, the first Pontryagin class in divisible by 2 in a canonical way. This implies that for 7d, the thermal hall conductivity for the fermionic case is half that of the bosonic case. Not sure how he reached this conclusion and if there are other general relations.

A basic remark is that \(7p_2(X)-p_1^2(X)\)has to be a multiple of \(45\), so it put constraints on \(p_1, p_2\). For instance, \(p_2=7, p_1=2\) is a possible choice...This will be in fact a more evident choice, if the A-genus would be zero, which would give : \(\hat{A}_2 = (-4p_2 + 7 p_1^2)/5760 = 0\).... 

But the point is that $2p_2-p_1^2$ runs through $\mathbb{Z}$, so the constraint you mentioned does not put any extra constraint on $k$.

oh wait, my last comment was wrong, it has to be multiples of 5. Sorry. So this does put some constraint on k.

Regarding the comment above on lifting to a higher group:

yes, what we discuss in section 4.5 of arXiv:1201.5277 is 7d Chern-Simons theory not on 1-form SO(N)-gauge fields but on 1- and 2-form gauge fields for what is called the "String 2-group" extension of SO(N). The argument is that by arXiv:1202.2455 this is the correct choice if the 7d CS theory is supposed to be that appearing from the nonabelian 1-loop term in the CS term of 11d supergravity (actually in the full story its a "\(\mathrm{String}^a\)"-2-group that matters, see the article for the details.).

And on these StringSO(N)-2-group 2-form connections, the prefactor in question is \(\frac{1}{6}\)

Thanks. This is really helpful.

Maybe to add that: the actual construction and theorem underlying this is in arXiv:1011.4735 This is a general machine that reads in an \((n+1)\)-cocylce \(\mu\) on an \(L_\infty\)-algebra \(\mathfrak{g}\)and spits out a fully local ("extended", "mult-tiered") \(n+1\)-dimensional Chern-Simons type Lagrangian for \(\mathfrak{g}\)-connections. 

Your answer

Please use answers only to (at least partly) answer questions. To comment, discuss, or ask for clarification, leave a comment instead.
To mask links under text, please type your text, highlight it, and click the "link" button. You can then enter your link URL.
Please consult the FAQ for as to how to format your post.
This is the answer box; if you want to write a comment instead, please use the 'add comment' button.
Live preview (may slow down editor)   Preview
Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
If you are a human please identify the position of the character covered by the symbol $\varnothing$ in the following word:
p$\varnothing$ysicsOverflow
Then drag the red bullet below over the corresponding character of our banner. When you drop it there, the bullet changes to green (on slow internet connections after a few seconds).
Please complete the anti-spam verification




user contributions licensed under cc by-sa 3.0 with attribution required

Your rights
...