Good question. The answer is that one can always (completely) symmetrize the integrand with respect to L! loop variables. For instance, the two-loop
1 2
\ x1 /
\_________/
| | |
x4 | y1 | y2 | x2
|____|____|
/ \
/ x3 \
4 3
integral in dual coordinates is (the numerator is chosen so that the integral is dual-conformally invariant):
∫d4y1d4y22!(x1−x3)4(x2−x4)2(y1−x3)2(y1−x4)2(y1−x1)2(y2−x1)2(y2−x2)2(y2−x3)2(y1−y2)2+(y1↔y2)
People usually write these integrals in momentum-twistor variables. As you remember, to each of the loop variables yi there is an associated pair of twistors (ZAi,ZBi). The above integral turns out to be
∫(A1B1,A2B2)⟨1234⟩2⟨2341⟩⟨A1B141⟩⟨A1B112⟩⟨A1B123⟩⟨A2B223⟩⟨A2B234⟩⟨A2B241⟩⟨A1B1A2B2⟩,
where
(A1B1,A2B2) means that the integration measure has a factor of
12! in it from the symmetrization
(A1B1↔A2B2.