Quantcast
  • Register
PhysicsOverflow is a next-generation academic platform for physicists and astronomers, including a community peer review system and a postgraduate-level discussion forum analogous to MathOverflow.

Welcome to PhysicsOverflow! PhysicsOverflow is an open platform for community peer review and graduate-level Physics discussion.

Please help promote PhysicsOverflow ads elsewhere if you like it.

News

PO is now at the Physics Department of Bielefeld University!

New printer friendly PO pages!

Migration to Bielefeld University was successful!

Please vote for this year's PhysicsOverflow ads!

Please do help out in categorising submissions. Submit a paper to PhysicsOverflow!

... see more

Tools for paper authors

Submit paper
Claim Paper Authorship

Tools for SE users

Search User
Reclaim SE Account
Request Account Merger
Nativise imported posts
Claim post (deleted users)
Import SE post

Users whose questions have been imported from Physics Stack Exchange, Theoretical Physics Stack Exchange, or any other Stack Exchange site are kindly requested to reclaim their account and not to register as a new user.

Public \(\beta\) tools

Report a bug with a feature
Request a new functionality
404 page design
Send feedback

Attributions

(propose a free ad)

Site Statistics

205 submissions , 163 unreviewed
5,082 questions , 2,232 unanswered
5,353 answers , 22,789 comments
1,470 users with positive rep
820 active unimported users
More ...

  Does string theory provide a physical regulator for Standard Model divergencies?

+ 6 like - 0 dislike
1600 views

In other question, Ron Maimon says that he thinks string theory is the physical regulator. I did not know that string theory regularize divergencies.

So, Q1: How does string theory regularize the ultra-violet divergencies of the "low-energy" (Standard Model) fields? And Q2: Why it doesn't regularize its own divergencies.

By regularization I mean that the theory is ultra-violet finite before removing the regulator.

This post imported from StackExchange Physics at 2014-04-05 04:14 (UCT), posted by SE-user drake
asked Sep 14, 2012 in Theoretical Physics by drake (885 points) [ no revision ]
retagged Apr 5, 2014
Supersymmetric string theories don't have a perturbative regulator, they have no ultraviolet divergences. There are infrared divergences, but these are understood from soft modes in the theory.

This post imported from StackExchange Physics at 2014-04-05 04:14 (UCT), posted by SE-user Ron Maimon

1 Answer

+ 5 like - 0 dislike

The answer to both questions is that string theory is completely free of any ultraviolet divergences. It follows that its effective low-energy descriptions such as the Standard Model automatically come with a regulator.

An important "technicality" to notice is that the formulae for amplitudes in string theory are not given by the same integrals over loop momenta as in quantum field theory. Instead, the Feynman diagrams in string theory are Riemann surfaces, world sheets, and one integrates over their possible conformal shapes (moduli).

Nevertheless, if one rewrites these integrals in a way that is convenient to extract the low-energy limit of string theory, one may see that the stringy diagrams boil down to the quantum field theory diagrams at low energies and the formulae are the same except for modifications that become large, $O(1)$, at energies of order $m_{\rm string}\sim \sqrt{T}$. The string scale is where perturbative string theory's corrections to quantum field theory become substantial and that's where the typical power-law increasing divergences in QFT are replaced by the exponentially decreasing, ultra-soft stringy behavior.

The reason/proof why/that string theory has no UV divergences has been known for decades. UV divergences would arise from extreme corners of the moduli space of Riemann surfaces in which the "length of various tubes" inside the degenerating Riemann surface would go to zero. But all such extreme diagrams are equivalent to diagrams with "extremely thin tubes" and may therefore be reinterpreted as IR divergences: it's the only right interpretation of these divergences and no "extra UV divergences" exist because it would be double-counting.

Bosonic string theory has infrared divergences due to the tachyon and dilaton and their long-range effects. However, in 10-dimensional superstring theory, one may prove that all the IR divergences – and there are just several a priori possible candidates that could be nonzero to start with – cancel, essentially due to supersymmetry. It follows that superstring theory is free of all divergences.

This post imported from StackExchange Physics at 2014-04-05 04:14 (UCT), posted by SE-user Luboš Motl
answered Sep 14, 2012 by Luboš Motl (10,278 points) [ no revision ]
Hi Lubos, it's a nice answer +1, but one has to mention that certain infrared divergences remain in diagrams when you have massless modes being produced in time-dependent processes, which are analogous in every way to QED infrared divergences, and no more worrisome.

This post imported from StackExchange Physics at 2014-04-05 04:14 (UCT), posted by SE-user Ron Maimon
Thanks, +1. So string theory is a regulator of the SM divergencies in the sense that it is an ultraviolet completion of the SM that is free of ultraviolet divergencies, right? It is not that it regulates the loop integrals of QFT providing a sort of cut-off (?)

This post imported from StackExchange Physics at 2014-04-05 04:14 (UCT), posted by SE-user drake
Nice explanation of cute cool things :-)!

This post imported from StackExchange Physics at 2014-04-05 04:14 (UCT), posted by SE-user Dilaton
Thanks, Ron, very true. Thanks, Dilaton! ;-) Drake: string theory does regulate the loop integrals, it's just doing so in a way that would be far from obvious in any field theory approach. But this new way of regulation is somewhat similar to brutal cutoffs with $\Lambda=m_{\rm string}$, at least when it comes to various estimates.

This post imported from StackExchange Physics at 2014-04-05 04:14 (UCT), posted by SE-user Luboš Motl
Thanks. It seems weird to me that a sharp cutoff does not violate and symmetry of the QFT... Do you know any reference where I can read more about this?

This post imported from StackExchange Physics at 2014-04-05 04:14 (UCT), posted by SE-user drake
@drake: The best reference is to Regge theory--- this is sketchily done in Green-Schwarz-Witten ch-1 and completely in Gribov's book "Theory of Complex Angular Momentum". String exchange can be thought of as an exchange of families of particles in ever higher angular momentum and mass, Regge trajectories, which together sum to an analytic amplitude which is soft in the large angle high-energy limit where field theory is hard. This is the 1960s motivation for strings, and it is the reason for no divergences. The modern interpretation is infrared/ultraviolet duality, which is some holography.

This post imported from StackExchange Physics at 2014-04-05 04:14 (UCT), posted by SE-user Ron Maimon

Your answer

Please use answers only to (at least partly) answer questions. To comment, discuss, or ask for clarification, leave a comment instead.
To mask links under text, please type your text, highlight it, and click the "link" button. You can then enter your link URL.
Please consult the FAQ for as to how to format your post.
This is the answer box; if you want to write a comment instead, please use the 'add comment' button.
Live preview (may slow down editor)   Preview
Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
If you are a human please identify the position of the character covered by the symbol $\varnothing$ in the following word:
p$\hbar$ysic$\varnothing$Overflow
Then drag the red bullet below over the corresponding character of our banner. When you drop it there, the bullet changes to green (on slow internet connections after a few seconds).
Please complete the anti-spam verification




user contributions licensed under cc by-sa 3.0 with attribution required

Your rights
...