I was reading through my notes on the path integral quantization of bosonic string theory when a general question about path integral quantization arised to me.
The widely used intuitive explanation of a path integral is that you sum over all paths from spacetime point x to spacetime point y. The classical path has weight one (is this correct?), whereas the quantum paths are weighed by exp(iS), where S is the action of the theory you are considering. In my current situation we have the Polyakov path integral:
Z=∫DXDgabeiSp[X,g],
where
Sp is the Polyakov action.
I have seen the derivation of the path integral by Matrix kernels in my introductory QFT course. A problem which occured to me is that if the quantum paths are really "weighted" by the
exp(iSp), it only makes sense if
Re(Sp)=0 and
Im(Sp)≠0. If this were not the case, the integral seems to be ill-defined (not convergent) and in the case of an oscillating exponential we cannot really talk about a weight factor right? Is this reasoning correct? Is the value of the Polyakov action purely imaginary for every field
Xμ and
gab?
Secondly, when one pushes through the calculation of the Polyakov path integral one obtains the partition function
ˆZ=∫DXDbDcei(Sp[X,g]+Sg[b,c]),
where we have a ghost action and the Polyakov action. My professor now states that this a third quantized version of string theory (we have seen covariant and lightcone quantization). I am wondering where the quantization takes place. Does it happen at the beginning, when one postulates the path integral on the grounds of similarity to QFT? I am looking for a well-defined point, like the promotion to operators with commutation relations in the lightcone quantization.
Finally, in a calculation of the Weyl anomaly and the critical dimension, the professor quantizes the ghost fields. This does not make sense to me. If the path integral is a quantization of string theory, why do we have to quantize the ghost fields afterwards again?
This post imported from StackExchange Physics at 2014-04-07 15:52 (UCT), posted by SE-user Funzies