Recall that dLIPS2 (one particle decaying into two particles of the same mass) is given by
dLIPS2=|k′1|16π2√sdΩcm.
In a given decay, is all the angle dependence included in dLIPS? If I recall correctly, this does not need be the case, or else the integration over the angles would always be trivial.
This post imported from StackExchange Physics at 2014-04-13 11:21 (UCT), posted by SE-user Love Learning