Quantcast
  • Register
PhysicsOverflow is a next-generation academic platform for physicists and astronomers, including a community peer review system and a postgraduate-level discussion forum analogous to MathOverflow.

Welcome to PhysicsOverflow! PhysicsOverflow is an open platform for community peer review and graduate-level Physics discussion.

Please help promote PhysicsOverflow ads elsewhere if you like it.

News

PO is now at the Physics Department of Bielefeld University!

New printer friendly PO pages!

Migration to Bielefeld University was successful!

Please vote for this year's PhysicsOverflow ads!

Please do help out in categorising submissions. Submit a paper to PhysicsOverflow!

... see more

Tools for paper authors

Submit paper
Claim Paper Authorship

Tools for SE users

Search User
Reclaim SE Account
Request Account Merger
Nativise imported posts
Claim post (deleted users)
Import SE post

Users whose questions have been imported from Physics Stack Exchange, Theoretical Physics Stack Exchange, or any other Stack Exchange site are kindly requested to reclaim their account and not to register as a new user.

Public \(\beta\) tools

Report a bug with a feature
Request a new functionality
404 page design
Send feedback

Attributions

(propose a free ad)

Site Statistics

205 submissions , 163 unreviewed
5,082 questions , 2,232 unanswered
5,353 answers , 22,789 comments
1,470 users with positive rep
820 active unimported users
More ...

  Spectrum with Hamiltonian that has a periodic potential

+ 3 like - 0 dislike
1822 views

Hi

If I have a Hamiltonian \(H=-\frac{d^2}{d \theta^2}+ V\) where the potential is a periodic function with periodic \(2 \pi \) and I know the ground state solution and ground state eigenvalue. Is there any canonical way how I could get all the other eigenvalues and eigenfunctions? The only I am aware of would be to introduce ladder operators, right? But is it possible to construct these kind of operators for arbitrary Hamiltonians? Or maybe there is a better method available for this kind of Hamiltonian?

asked May 17, 2014 in Theoretical Physics by Lefschetz (50 points) [ revision history ]
edited May 18, 2014 by Lefschetz

1 Answer

+ 4 like - 0 dislike

Check out Bloch's theorem which tells you how to handle periodic potentials. This is a standard problem in condensed matter physics where one is dealing with electrons moving in a lattice and hence any standard book on Condensed Matter Physics will have something on this. The ladder operator method will only work for special one-dimensional potentials of the form $ V(x) = W(x)^2 \pm  W'(x)$ that appear in the context of supersymmetric quantum mechanics. Right?

answered May 18, 2014 by suresh (1,545 points) [ no revision ]

Bloch's theorem does not help much I think. It only helps for potentials that are periodic with respect to translation, this potential is rotational symmetric (therefore the 2 pi), hence you do not gain much from this. Your second argument looks interesting. If you have this W how do you get your ladder operator?

If you have translational invariance in one-dimension with translational period $2\pi$ -- it is identical to being on a circle with circumference $2\pi$. Think about it! (There are many reviews on susy QM -- just do an internet search.)

true, but how should it help me finding the ladder operators and spectrum? Bloch's theorem tells me then that I can split it up into \(e^{ik 2\pi}u(\theta), \) where u itself is 2pi periodic. So how does this help finding the full spectrum of a hamiltonian like \(H = -\frac{d^2}{d \theta^2}+ \sin(\theta)+sin^2(\theta) + \sin^{50}(\theta) \)?

I agree with your statement about Bloch's theorem. Who said that there must exist ladder operators for your example? Can you give me a reference? I doubt if there is one for a generic potential.  Anyway, here is a paper that deals with ladder operators but I doubt if your example will show up there.

@Lefschetz: Could you be more specific about the Hilbert space of your problem? It does make a difference whether the particle moves on an infinite line in a periodic potential, or whether it moves on a circle. (The latter restricts the boundary conditions of the wave function to \(ψ(θ+2π)=ψ(θ)\)while the former does not.)

Your answer

Please use answers only to (at least partly) answer questions. To comment, discuss, or ask for clarification, leave a comment instead.
To mask links under text, please type your text, highlight it, and click the "link" button. You can then enter your link URL.
Please consult the FAQ for as to how to format your post.
This is the answer box; if you want to write a comment instead, please use the 'add comment' button.
Live preview (may slow down editor)   Preview
Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
If you are a human please identify the position of the character covered by the symbol $\varnothing$ in the following word:
p$\hbar$ys$\varnothing$csOverflow
Then drag the red bullet below over the corresponding character of our banner. When you drop it there, the bullet changes to green (on slow internet connections after a few seconds).
Please complete the anti-spam verification




user contributions licensed under cc by-sa 3.0 with attribution required

Your rights
...