Substitution in the following supersymmetry transformation rule

Question

I was reading in this book: Supergravity for Daniel Freedman and was checking the part that has to do with Extremal Reissner Nordstrom Black Hole. He was using killing spinors (that I am very new to).

I was understanding the theory until he stated with the calculations:

He said that the Supersymmetry transformation (21.49) in his book is:

$$\delta \psi_\mu^i=(\partial_\mu +1/4 \gamma^{ab}\omega_{\mu ab})\epsilon^i -1/8\sqrt{2}\kappa \gamma^{ab}F_{ab}\epsilon^{ij} \gamma_\mu \epsilon_j$$

He then started "It is convenient to work with the chiral projections of the two Majo-rana spinors. We thus use the up/down position of the R-symmetry indices, now denoted by (A, B=1, 2), to specify the chirality. Thus, for the SUSY transformation parameters, we have"

$\gamma_* \epsilon^A= P_L \epsilon^A = \epsilon^A$ and $\gamma_* \epsilon_A= - P_R \epsilon_AA = - \epsilon_A$ where $\gamma_*$ is the usual $\gamma_5$ and $P_L$ and $P_R$ are projection operators to define chiral parts.

So back to the first equation that I wrote here: He substituted it with:

$$\delta \psi_{tA} = \partial_t \epsilon _A +1/2 e^{2U} \partial_i U\gamma^i \gamma^0 \epsilon_A -1/4 \sqrt{2}\kappa e^u \partial_i A_t \gamma^i \epsilon_{AB} \epsilon^b =0$$

It is specifically the substitutions that I could not follow, where did the gamma matrices in the last equation come from?

Concerning the spin conection I found them to be: $\omega^{0i} = e^U \partial_iU e^0$ and $\omega ^{ij} = -dx^i\partial_jU+dx^j\partial_iU$ and they each have 2 indices while in the supersymmetry transformation equation the omega has 3 indices. I know I am missing something and I hope you can help me understand the substitution better.

This post imported from StackExchange Physics at 2014-12-01 21:47 (UTC), posted by SE-user Fluctuations