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  Green function for single impurity

+ 1 like - 0 dislike
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I am working on the first problem on self-consistent T-matrix approximation in Chapter 5 of Condensed Matter Field Theory by Altland and Simons. This is on page 234 of the textbook. I have some questions regarding part (a).

The Hamiltonian of the problem is ˆH=ˆH0+ˆHimp, where

ˆH0=kϵkckck,

ˆHimp=v0adNimpi=1c(Ri)c(Ri), Nimp is the number of impurities.

The goal is to compute the single-particle Green function Gn=cn(r)cn(r)imp, where n is the Matsubara frequency index and imp1LdiddRi is the configurational average over all impurity coordinates.

Here is the problem statement of part (a)

Consider the scattering from a single impurity. By developing a perturbative expansion in the impurity potential, show that the Green function can be written as ˆGn=ˆG0,n+ˆG0,nˆTnˆG0,n, where

ˆTn=ˆHimp+ˆHimpˆG0,nˆHimp+ˆHimpˆG0,nˆHimpˆG0,nˆHimp+imp

denotes the T-matrix. Show that the T-matrix equation is solved by Tn(r,r)=δ(rr)Ld((v0ad)1G0,n(0))1.

Here are my questions:

(1) The answer gives a hint about approaching the problem by representing the Green function Gn=cn(r)cn(r)imp in coherent state path integral, where n is the Matsubara frequency index. The textbook states that the formal result after integrating over Grassmann field is ˆGn=(iωnˆH0ˆHimp)1. In my understanding, the coherent state path integral always yields a number. Is there a formal procedure for reverting the scalar back to operator? Or after obtaining the actual number, how should I proceed with the perturbation expansion?

(2) When evaluating the path integral, do I treat cn(r)cn(r) as Grassmann variable ˉψn(r)ψn(r)? Should I fourier transform ˆHimp first?

(3) I don't see why the diagram in Fig. 5.11 is relevant for a single impurity.It looks more like the diagram for scattering off multiple impurities. Is this an error?

The diagram is shown in the image. Diagram


This post imported from StackExchange Physics at 2014-12-10 17:33 (UTC), posted by SE-user chicane

asked Dec 9, 2014 in Theoretical Physics by chicane (5 points) [ revision history ]
edited Dec 11, 2014 by dimension10
Since not everyone has that book, it might be more useful to include more information (e.g., copy question verbatim, include Fig. 5.11) than just limiting the potential answerers to those who have a copy of the book.

This post imported from StackExchange Physics at 2014-12-10 17:33 (UTC), posted by SE-user Kyle Kanos
I can recommend looking at the book "Green's functions in quantum physics" by Economou, I think he discusses this problem and the underlying theory in terms of resolvent operators in quite some detail. What you have written above is called the resolvent operator. The Green's functions are simply the expectation values of this in a suitable single-particle (or two-particle etc.) basis.

This post imported from StackExchange Physics at 2014-12-10 17:33 (UTC), posted by SE-user ulf
@KyleKanos Thanks for the advice. I have included the problem statement and the diagram.

This post imported from StackExchange Physics at 2014-12-10 17:33 (UTC), posted by SE-user chicane
@dimension10, the picture is not properly sized.
@JiaYiyang Thanks, fixed.

1 Answer

+ 3 like - 0 dislike

You may notice that they are re-deriving the Dyson equation (or whatever it is called): G(b,a)=G0(b,a)+dcG(b,c)V(c)G0(c,a),

where a,b,c denote complete sets of indices, say in this case (r,τ), G(b,a)=Tψ(b)ψ(a), and V is an external potential. This equation is one that can be used to derive Feynman's rules and it can be easily derived just by equation of motion of the Hamiltonian operator. (If you are interested, check Chapter 11, Many-body quantum theory in condensed matter physics. ) Anyway, let me try to answer your questions:

(1) Yes, Gn(r,r)=cn(r)cn(r)imp is a scalar for fixed r and r, but if we treat r and r as indices, Gn(r,r) can also be regarded an infinite-dimensional matrix (an operator if you prefer, but in a different sense, depending on which space it acts.) For clarification, let me show all indices explicitly in the relation: ˆG(r,r)=1iωnδ(rr)ˆH0(r,r)ˆHimp(r,r)=1ˆG10(r,r)[1ˆG0(r,r)ˆHimp(r,r)].

Summation over repeated indices is assumed. The expansion should also carry these indices with caution. After that, you can get the expression for ˆG(r,r).

(2) Notice that there are always two common ways to evaluate Green's functions (correlation functions, propagators...), namely, using operators and using functional integration (path integral). If you do not know the difference, compare Eq(4.31) with Eq(9.18) in Peskin and Schroeder. In path integral, these fields are scalars.

(3) Yes. You are right. It seems to me that the ''scattering lines'' should connect to a single point. Hope this can help :~)

answered Dec 16, 2014 by DarKnightS (125 points) [ revision history ]
edited Dec 17, 2014 by DarKnightS
Minorly edited:

1.Enclosed punctuations in begin{equation} end{equation}

2.Embedded links into texts.(To do this you can first highlight the targeted texts and then click on the "link" icon on top of the text editor box, the icon looks a bit like .)

3. Splitted points (1)(2)(3) to different paragraphs.
Thank you. Technique learned.

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