Quantcast
  • Register
PhysicsOverflow is a next-generation academic platform for physicists and astronomers, including a community peer review system and a postgraduate-level discussion forum analogous to MathOverflow.

Welcome to PhysicsOverflow! PhysicsOverflow is an open platform for community peer review and graduate-level Physics discussion.

Please help promote PhysicsOverflow ads elsewhere if you like it.

News

PO is now at the Physics Department of Bielefeld University!

New printer friendly PO pages!

Migration to Bielefeld University was successful!

Please vote for this year's PhysicsOverflow ads!

Please do help out in categorising submissions. Submit a paper to PhysicsOverflow!

... see more

Tools for paper authors

Submit paper
Claim Paper Authorship

Tools for SE users

Search User
Reclaim SE Account
Request Account Merger
Nativise imported posts
Claim post (deleted users)
Import SE post

Users whose questions have been imported from Physics Stack Exchange, Theoretical Physics Stack Exchange, or any other Stack Exchange site are kindly requested to reclaim their account and not to register as a new user.

Public \(\beta\) tools

Report a bug with a feature
Request a new functionality
404 page design
Send feedback

Attributions

(propose a free ad)

Site Statistics

205 submissions , 163 unreviewed
5,082 questions , 2,232 unanswered
5,353 answers , 22,789 comments
1,470 users with positive rep
820 active unimported users
More ...

  Transition rates when interaction with a measuring device is taken into account

+ 3 like - 0 dislike
1202 views

This is essentially a reiteration of this question posed on SE, which has not received a complete answer yet.

In some circumstances (cfr. Qmechanic's answer in the link above), in time dependent perturbation theory, one can define a “transition rate” beetween eigenstates of the unperturbed energy of the system. By definition, this rate refers to the free unitary evolution of the (perturbed) system, i.e. when no measurement is being made upon the system.

On the other hand, if the number of such transitions is being somehow counted, this means that the system is interacting with some device which leads to decoherence beetween the “initial” and “final” states of perturbation theory. For example, if the process in question is the beta decay of a neutron, the number of decays in a sample of neutrons could be monitored by detecting the protons emitted in the decay. It is clear that a complete quantum description of a transition process requires the interaction with the measuring device to be taken into account and, in general, the resulting (non-unitary) dynamic for the state of the system can be very different from the simple one described by a transition rate.

Therefore, my question is: under what assumptions about the interaction with the measuring device (i.e. on the interaction hamiltonian, the decoherence time of initial and final states etc.)  is it still possible to meaningfully talk of a “transition rate”? 

In brief, the transition rate describes this situation: $$H=H_0 + H_{\text {pert}},\qquad \lvert i \rangle \longrightarrow \sqrt {1-wt} \lvert i \rangle+\sqrt{wt}\lvert f \rangle,$$ where $i$ and $f$ are eigenstates of $H_0$. Taking into account the interaction with a measuring device, we should have something like $$H=H_0+H_{\text {pert}} +H_{\text {int}} ,\qquad \lvert i \rangle \longrightarrow (1-wt) \lvert i \rangle \langle i \rvert +wt \lvert f \rangle \langle f \rvert.$$ Under what assumptions on $H_{\text{int}}$ is the above equation true?

asked Jan 5, 2016 in Phenomenology by pppqq2q (15 points) [ revision history ]

@VladimirKalitvianski: This is unrelated to the question. please start a new thread if you want to discuss this.

How many downvotes and how much hate for my "mistake". Have I written a wrong thing on purpose? I just shared what I knew.

You share it on a thread where it is off-topic. Post a new thread, under 'Recommendations', and it will be acceptable since it may be useful information. That's what the recommendation category is for.

Your answer

Please use answers only to (at least partly) answer questions. To comment, discuss, or ask for clarification, leave a comment instead.
To mask links under text, please type your text, highlight it, and click the "link" button. You can then enter your link URL.
Please consult the FAQ for as to how to format your post.
This is the answer box; if you want to write a comment instead, please use the 'add comment' button.
Live preview (may slow down editor)   Preview
Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
If you are a human please identify the position of the character covered by the symbol $\varnothing$ in the following word:
p$\hbar$ysicsOverf$\varnothing$ow
Then drag the red bullet below over the corresponding character of our banner. When you drop it there, the bullet changes to green (on slow internet connections after a few seconds).
Please complete the anti-spam verification




user contributions licensed under cc by-sa 3.0 with attribution required

Your rights
...