The answer given above is somewhat incomplete, in that it doesn't answer the question. Independently of the fact that expanding around a flat background is equivalent to inserting an exponential of a graviton vertex operator (which was nicely reviewed by @Frederic Brünner above), the question is **why is this a coherent state and what is the definition of a coherent state in this context**.

The word coherent state (in string theory and beyond) has a very precise meaning: any coherent state must:

**(1)** depend on continuous quantum numbers (position and momentum do not qualify as continuous because there does not exist a smooth limit for the corresponding 2-pt amplitudes*);

**(2)** there should exist a resolution of unity with respect to these quantum numbers.

Since the above state, $\exp(-V)$, does not satisfy these conditions (as it stands) it is not a coherent state and we have to work harder.
Secondly, my understanding is that eigenstates of annihilation operators do not exist in closed string theory** (there is a global obstruction that is the Euler number), for the same reason that charged coherent states are not eigenstates of annihilation operators (in standard quantum mechanics), the relevant charge in the string case being $L_0-\tilde{L}_0$. The above definition (associated to the continuous quantum numbers) nevertheless applies for all coherent states in string theory and beyond. So for all these reasons, the honest answer is that the connection between string coherent states and curved backgrounds is not well understood (and the answer is certainly not in any popular qualitative lecture notes). In fact the question is a very good one.

Nevertheless, one can make progress. Firstly there are two types of coherent states in string theory: coherent states of string fields and coherent states of modes on a single string, both of which have vertex operator realisations. The former is more general than the latter (the former is non-local on the worldsheet and in spacetime whereas the latter is only non-local in spacetime), but there is a corner in moduli space where there are equivalent. The coherent states of modes on a single string have been constructed and are only now starting to become understood (see https://arxiv.org/abs/1304.1155 and refs therein). Coherent states of string fields are much much less well understood and i do not know of any reference. The relation of coherent states to curved backgrounds is in principle understood but in practice remains elusive. Needless to say, there are groups around the world working on this very interesting question because it provides one of the few quantum gravity handles associated to non-trivial backgrounds (and clearly does not assume validity of low energy effective field theory as the approach is entirely stringy).

*For example, in flat spacetime and for momentum eigenstates the overlap is proportional to a delta function in momenta.

** This is true in standard gauges, such as covariant or lightcone gauge, and is in fact an offshell statement (and hence very difficult to circumvent). It is simply the statement that $L_0-\tilde{L}_0$ doesn't commute with the annihilation operators, and therefore there cannot exist simultaneous eigenstates of annihilation operators and of $L_0-\tilde{L}_0$. Given that invariance under the latter is more fundamental (for the reason mentioned above), the conclusion follows (https://arxiv.org/abs/1006.2559). I should mention there are gauges where this is not the case (such as static gauge), but here one does not know how to quantise the string beyond an ''effective theory type'' of quantisation. Another possible way out is to compactify a lightlike direction of spacetime, known as DLCQ quantisation in the M-theory literature but again there are fundamental difficulties in trying to make sense of this at the quantum level (https://arxiv.org/abs/hep-th/9711037). So this is why I say eigenstates of annihilation operators do not exist in closed string theory.

This post imported from StackExchange Physics at 2018-03-02 22:48 (UTC), posted by SE-user Wakabaloola