Quantcast
  • Register
PhysicsOverflow is a next-generation academic platform for physicists and astronomers, including a community peer review system and a postgraduate-level discussion forum analogous to MathOverflow.

Welcome to PhysicsOverflow! PhysicsOverflow is an open platform for community peer review and graduate-level Physics discussion.

Please help promote PhysicsOverflow ads elsewhere if you like it.

News

PO is now at the Physics Department of Bielefeld University!

New printer friendly PO pages!

Migration to Bielefeld University was successful!

Please vote for this year's PhysicsOverflow ads!

Please do help out in categorising submissions. Submit a paper to PhysicsOverflow!

... see more

Tools for paper authors

Submit paper
Claim Paper Authorship

Tools for SE users

Search User
Reclaim SE Account
Request Account Merger
Nativise imported posts
Claim post (deleted users)
Import SE post

Users whose questions have been imported from Physics Stack Exchange, Theoretical Physics Stack Exchange, or any other Stack Exchange site are kindly requested to reclaim their account and not to register as a new user.

Public \(\beta\) tools

Report a bug with a feature
Request a new functionality
404 page design
Send feedback

Attributions

(propose a free ad)

Site Statistics

205 submissions , 163 unreviewed
5,082 questions , 2,232 unanswered
5,353 answers , 22,789 comments
1,470 users with positive rep
820 active unimported users
More ...

  Example of transcendental equation in Physics

+ 0 like - 0 dislike
3112 views

Hello, everyone, 

I was asked by my numerical calculus teacher (undergraduate course) to solve for roots of a transcendental or a non-linear equation using some numerical method. The problem is that this equation has to be related with physics, and I don't know any equation of this kind in physics (unfortunately, I don't have a deep knowlege in physics yet); actually, the ones I know involve differential and integral calculus, so they would require more advanced methods that I don't know yet. So, could you guys provide me with an equation of such kind? You don't have to explain the physics behind it if you don't want to; I just need the equation and its name (or something that specifies it) - the theory behind it I can search myself. 

Just some points concerning this problem: the equation should not be a differential or an integral equation; and it should be (please) an easy one (especially, an one variable one), because I will have to apply this numerical method both with and without a computer (to compare the results), which means that a hard equation could lead to a problem that I could not answer without a computer.

Thank you for your attention to this matter.

asked Sep 7, 2018 in General Physics by Lucas [ no revision ]

3 Answers

+ 1 like - 0 dislike

I can add the simplest example: $$\sin(kx_1)=\sin(k(L-x_1))\qquad (1).$$ The first $\sin$ is a solution turning into zero at $x=0$, the second one turns into zero at $x=L$. This is a solution for an elastic guitare string fixed at $x=0$ and $x=L$. At $x=x_1$ we require continuety of the total solution; thus the equation (1). You must find the possible values of $k_n$ to satisfy this equation.

answered Sep 8, 2018 by Vladimir Kalitvianski (102 points) [ revision history ]

Great! Thank you very much, @VladimirKalitvianski ! :) (I'm the question author) 

Note, the possible discrete values of $k$ will not depend on $x_1$ since I proposed the case of a uniform string. Still, it is interesting to make sure that it is so and compare with the analytical solutions $\sin(k_nx)$ where $k_n=\pi\cdot n/L$, $n=1, 2, 3,...$.

In  fact, the continuety equation should read as follows: $$\sin(kx_1)=\pm\sin(k(L-x_1))\qquad (1).$$

+ 1 like - 0 dislike

The expected spin using mean field theory in the Ising model. For spin $\sigma$ between negative one and one, external magnetic field $B$, spin coupling $J$, and temperature $T$, we have:

$$\langle \sigma \rangle =\tanh \left(\frac{ J \langle \sigma \rangle+B}{k_B T} \right)$$

If you plot this for different temperatures, you'll see exactly how the phase transition happens. It has one solution for high temperatures but three (with one solution unstable) for low temperatures.
 

answered Sep 27, 2018 by connornm777 (30 points) [ revision history ]
+ 0 like - 0 dislike

It happens quite often in quantum mechanics, but I guess you are not that advanced in physics.  :-)

OK, in electricity I can come up with a diode (Shockley diode equation) connected to a generator.

The diode lets current i = i_0 (exp (V / V0) - 1).  (Note: In introductory courses you probably see that a diode lets i=0 for V < V0 and whatever current for V = V0.)    We also know that the voltage is V = v - ri (the generator has internal resistance r, so that the voltage is a bit smaller than nominal voltage v).  Thus i = (v - V) / r so that you get the equation:

     (v - V) = r i_0 (exp(V/V0) - 1).

answered Sep 8, 2018 by anonymous [ no revision ]

Perfect! Thank you ever so much! :) (I'm the question author)

Your answer

Please use answers only to (at least partly) answer questions. To comment, discuss, or ask for clarification, leave a comment instead.
To mask links under text, please type your text, highlight it, and click the "link" button. You can then enter your link URL.
Please consult the FAQ for as to how to format your post.
This is the answer box; if you want to write a comment instead, please use the 'add comment' button.
Live preview (may slow down editor)   Preview
Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
If you are a human please identify the position of the character covered by the symbol $\varnothing$ in the following word:
p$\hbar$ysicsOverflo$\varnothing$
Then drag the red bullet below over the corresponding character of our banner. When you drop it there, the bullet changes to green (on slow internet connections after a few seconds).
Please complete the anti-spam verification




user contributions licensed under cc by-sa 3.0 with attribution required

Your rights
...