Quantcast
  • Register
PhysicsOverflow is a next-generation academic platform for physicists and astronomers, including a community peer review system and a postgraduate-level discussion forum analogous to MathOverflow.

Welcome to PhysicsOverflow! PhysicsOverflow is an open platform for community peer review and graduate-level Physics discussion.

Please help promote PhysicsOverflow ads elsewhere if you like it.

News

PO is now at the Physics Department of Bielefeld University!

New printer friendly PO pages!

Migration to Bielefeld University was successful!

Please vote for this year's PhysicsOverflow ads!

Please do help out in categorising submissions. Submit a paper to PhysicsOverflow!

... see more

Tools for paper authors

Submit paper
Claim Paper Authorship

Tools for SE users

Search User
Reclaim SE Account
Request Account Merger
Nativise imported posts
Claim post (deleted users)
Import SE post

Users whose questions have been imported from Physics Stack Exchange, Theoretical Physics Stack Exchange, or any other Stack Exchange site are kindly requested to reclaim their account and not to register as a new user.

Public \(\beta\) tools

Report a bug with a feature
Request a new functionality
404 page design
Send feedback

Attributions

(propose a free ad)

Site Statistics

205 submissions , 163 unreviewed
5,082 questions , 2,232 unanswered
5,354 answers , 22,789 comments
1,470 users with positive rep
820 active unimported users
More ...

  why no double counting of s- and t-channels in string theory?

+ 4 like - 0 dislike
432 views

In string theory for the four particle tree diagram exchange, why is there some mysterious crossing duality between the s- and t- and u-channels? Why isn't there a double counting in the Feynman diagrams? How is this consistent with a quantum field theoretic description?

This post has been migrated from (A51.SE)
asked Nov 3, 2011 in Theoretical Physics by York (20 points) [ no revision ]

1 Answer

+ 5 like - 0 dislike

Let's consider the scattering of four (two to two) open strings, for the sake of concreteness.

Using Feynman's approach to quantum mechanics in terms of the sum over histories, string theory commands us to compute the tree-level diagram as the sum over all histories – world sheets – where two initial open strings become two other open strings.

By conformal transformations and the Wick rotation, each such history may be transformed to a disk diagram where the 4 external strings may be mapped to 4 points on the boundary of the disk.

The field theory limit is reproduced if these 4 insertions are pairwise close to each other. If 1-2 are close to each other as well as 3-4, we have an $s$-channel. Similarly for $t$-channel and $u$-channel. However, the string diagram unifies all these channels into a single integral; all these contributions are continuously connected to each other within string theory.

If one strictly rewrites string theory as a field theory with infinitely many fields and if one includes all the fields (infinitely many of them) that may occur as intermediate particles in the $s$-channels, then one may reproduce the Veneziano amplitude in this way. However, including all the infinitely many intermediate particles means that we are allowed to go away from the limit where 1-2 are close to each other, much like 3-4. The summing over all the heavy intermediate particles reproduces the whole stringy diagram with arbitrary positions of the 4 insertions.

That's why the $s$-channel, even in the field-theoretical language with infinitely many fields, already contains all the tree-level contributions and including the $t$-channel and $u$-channel diagrams separately would be a double- (or triple-) counting. This may be counterintuitive because in field theory, we're used to the idea that all three channels have to be included separately and again for unitarity.

However, string theory, because of its infinite number of fields and their new relationships, isn't quite equivalent to a field theory in this sense and one may check that the right unitarity is reproduced if the stringy diagram is only calculated once.

This post has been migrated from (A51.SE)
answered Nov 3, 2011 by Luboš Motl (10,278 points) [ no revision ]

Your answer

Please use answers only to (at least partly) answer questions. To comment, discuss, or ask for clarification, leave a comment instead.
To mask links under text, please type your text, highlight it, and click the "link" button. You can then enter your link URL.
Please consult the FAQ for as to how to format your post.
This is the answer box; if you want to write a comment instead, please use the 'add comment' button.
Live preview (may slow down editor)   Preview
Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
If you are a human please identify the position of the character covered by the symbol $\varnothing$ in the following word:
p$\hbar$ysicsOverf$\varnothing$ow
Then drag the red bullet below over the corresponding character of our banner. When you drop it there, the bullet changes to green (on slow internet connections after a few seconds).
Please complete the anti-spam verification




user contributions licensed under cc by-sa 3.0 with attribution required

Your rights
...