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  Chern-Simons term in the Coulomb or radiation gauge

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In some of the literature (for example, below Eq. (A3) of this paper), the following is claimed to be the Chern-Simons term in the Coulomb gauge:
2a0(1a22a1)
and it cited this paper, which below its Eq. (5) states that the above term is the Chern-Simons term in radiation gauge.

My questions are:

1. Is the radiation gauge the same as the Coulomb gauge, where 1a1+2a2=0.

2. Why is the above term the Chern-Simons in the Coulomb gauge? The standard Chern-Simons term is 
ϵμνλaμνaλ=a0(1a22a1)+a1(2a00a2)+a2(0a11a0)
After integrating by parts it becomes 
ϵμνλaμνaλ2a0(1a22a1)+2a20a1
which still differs from 2a0(1a22a1) by the last term that does not seem to vanish in the Coulomb gauge.

asked Apr 9, 2020 in Theoretical Physics by Mr. Gentleman (270 points) [ no revision ]
retagged Apr 10, 2020 by Mr. Gentleman

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