Quantcast
  • Register
PhysicsOverflow is a next-generation academic platform for physicists and astronomers, including a community peer review system and a postgraduate-level discussion forum analogous to MathOverflow.

Welcome to PhysicsOverflow! PhysicsOverflow is an open platform for community peer review and graduate-level Physics discussion.

Please help promote PhysicsOverflow ads elsewhere if you like it.

News

PO is now at the Physics Department of Bielefeld University!

New printer friendly PO pages!

Migration to Bielefeld University was successful!

Please vote for this year's PhysicsOverflow ads!

Please do help out in categorising submissions. Submit a paper to PhysicsOverflow!

... see more

Tools for paper authors

Submit paper
Claim Paper Authorship

Tools for SE users

Search User
Reclaim SE Account
Request Account Merger
Nativise imported posts
Claim post (deleted users)
Import SE post

Users whose questions have been imported from Physics Stack Exchange, Theoretical Physics Stack Exchange, or any other Stack Exchange site are kindly requested to reclaim their account and not to register as a new user.

Public \(\beta\) tools

Report a bug with a feature
Request a new functionality
404 page design
Send feedback

Attributions

(propose a free ad)

Site Statistics

205 submissions , 163 unreviewed
5,082 questions , 2,232 unanswered
5,354 answers , 22,789 comments
1,470 users with positive rep
820 active unimported users
More ...

  Anti-commutator version of Zassenhaus formula

+ 0 like - 0 dislike
1178 views

The Zassenhaus formula goes like $$ e^{t(X+Y)}= e^{tX}~ e^{tY} ~e^{-\frac{t^2}{2} [X,Y]} ~ e^{\frac{t^3}{6}(2[Y,[X,Y]]+ [X,[X,Y]] )} ~ e^{\frac{-t^4}{24}([[[X,Y],X],X] + 3[[[X,Y],X],Y] + 3[[[X,Y],Y],Y]) } \cdots, $$ where $X$ and $Y$ are operators may not commute.

Do people know and derive the anti-commutator version of Zassenhaus formula that expresses in terms of anti-commutator $\{X,Y\}$ in a very compact form?

I haven't found it on the literature (yet).

(1) Let us consider Grassmann-parity of $X$ and $Y$ are both even, so that $X$ and $Y$ both contain even number of fermionic operators $f/f^\dagger$, where $$ \{f_i,f_j^\dagger\}=\delta_{ij} $$

(2) What if $X$ or $Y$ contain an odd number of fermionic operators?

This post imported from StackExchange Physics at 2020-10-30 22:42 (UTC), posted by SE-user annie marie heart
asked Nov 15, 2017 in Theoretical Physics by annie marie heart (1,205 points) [ no revision ]
Such an expansion is (in general) impossible.

This post imported from StackExchange Physics at 2020-10-30 22:42 (UTC), posted by SE-user AccidentalFourierTransform
There cannot be any such general formula unless you specify some special properties of $X$ and $Y$. The formula for a commutator exists because it is associated with adjoint action of a group.

This post imported from StackExchange Physics at 2020-10-30 22:42 (UTC), posted by SE-user Prahar
What's the Grassmann-parity of $X$ and $Y$?

This post imported from StackExchange Physics at 2020-10-30 22:42 (UTC), posted by SE-user Qmechanic
Let us consider Grassmann-parity of X and Y are both even.

This post imported from StackExchange Physics at 2020-10-30 22:42 (UTC), posted by SE-user annie marie heart
$\{f_i,f_j^\dagger\}=\delta_{ij}$ is then not relevant for $\{X,Y\}$.

This post imported from StackExchange Physics at 2020-10-30 22:42 (UTC), posted by SE-user Qmechanic
In that even parity case, one can expand in terms of the sub-operators.

This post imported from StackExchange Physics at 2020-10-30 22:42 (UTC), posted by SE-user annie marie heart

Your answer

Please use answers only to (at least partly) answer questions. To comment, discuss, or ask for clarification, leave a comment instead.
To mask links under text, please type your text, highlight it, and click the "link" button. You can then enter your link URL.
Please consult the FAQ for as to how to format your post.
This is the answer box; if you want to write a comment instead, please use the 'add comment' button.
Live preview (may slow down editor)   Preview
Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
If you are a human please identify the position of the character covered by the symbol $\varnothing$ in the following word:
p$\hbar$ysicsOverf$\varnothing$ow
Then drag the red bullet below over the corresponding character of our banner. When you drop it there, the bullet changes to green (on slow internet connections after a few seconds).
Please complete the anti-spam verification




user contributions licensed under cc by-sa 3.0 with attribution required

Your rights
...