Quantcast
  • Register
PhysicsOverflow is a next-generation academic platform for physicists and astronomers, including a community peer review system and a postgraduate-level discussion forum analogous to MathOverflow.

Welcome to PhysicsOverflow! PhysicsOverflow is an open platform for community peer review and graduate-level Physics discussion.

Please help promote PhysicsOverflow ads elsewhere if you like it.

News

PO is now at the Physics Department of Bielefeld University!

New printer friendly PO pages!

Migration to Bielefeld University was successful!

Please vote for this year's PhysicsOverflow ads!

Please do help out in categorising submissions. Submit a paper to PhysicsOverflow!

... see more

Tools for paper authors

Submit paper
Claim Paper Authorship

Tools for SE users

Search User
Reclaim SE Account
Request Account Merger
Nativise imported posts
Claim post (deleted users)
Import SE post

Users whose questions have been imported from Physics Stack Exchange, Theoretical Physics Stack Exchange, or any other Stack Exchange site are kindly requested to reclaim their account and not to register as a new user.

Public \(\beta\) tools

Report a bug with a feature
Request a new functionality
404 page design
Send feedback

Attributions

(propose a free ad)

Site Statistics

205 submissions , 163 unreviewed
5,047 questions , 2,200 unanswered
5,345 answers , 22,709 comments
1,470 users with positive rep
816 active unimported users
More ...

  Dose Einstein's B coefficient determine the value of alpha?

+ 0 like - 1 dislike
540 views

Dose Einstein's B coefficient determine the value of alpha?

Einstein's B coefficient can be expressed as oscillator strength - \(f\) (a dimensionless value that expresses the probability transitions between energy levels).

\(B_x=\frac{c^3}{h\;\nu^2_x}= \frac{k_e\;e^2}{m_e\;h\;\upsilon_{x}}\;f\)

Solving for oscillator strength in terms of frequency we get;

\(f =\frac{m_e\;c^3}{k_e\;e^2}\frac{1}{\upsilon_x}=\left[\frac{\alpha_G^{0.5}}{\alpha} \nu_P\right]\frac{1}{\nu_x}=\frac{1.1\times 10^{23}}{\upsilon_x}\)

By oscillating the B coefficient's radiation field at specific frequencies we obtain;

Compton Frequency

\(\bar{\upsilon}_C\;\;{then}\;\;\;f_C=\frac{1}{\alpha}\)

Electron Be Frequency

\(\upsilon_{B_e}\;\;{then}\;\;\;f_{B_e}={\sqrt{\alpha}}\)

Planck Frequency

\(\upsilon_P\;\;{then}\;\;\;f_P=\frac{\sqrt{\alpha_G}}{\alpha}\)

From the above the value alpha is a resonant frequency of Einstein's B coefficient radiation field.

Another resonant frequency of Einstein's B coefficient radiation field generates a gravitational field.

Note

\(B_{e}=\dfrac{r_{e}}{m_{e}}=\dfrac{c^{3}}{h\;\nu^2_e}\)

asked Jul 21, 2022 in Theoretical Physics by Hyperthought (5 points) [ no revision ]

2 Answers

+ 0 like - 0 dislike

All dimensionless and dimensionful "numbers" must follow naturally from the corresponding equations. Then they have clear physical meaning. Simply combining the numbers as you like is a numerology, and thus it is void of physical meaning.

answered Jul 24, 2022 by Vladimir Kalitvianski (102 points) [ revision history ]
edited Jul 24, 2022 by Vladimir Kalitvianski
+ 0 like - 0 dislike

Applying the cosmological constant to the oscillator strength model gives us;

\(f =\frac{m_e\;c^3}{k_e\;e^2}\frac{1}{\upsilon_x}=\left[\frac{\alpha_G^{0.5}}{\alpha} \nu_P\right]\frac{1}{\nu_x}=\frac{1.1\times 10^{23}}{\upsilon_x}\)

Cosmological Constant

\(\upsilon_{\Lambda}\;\;{then}\;\;\;f_{\Lambda}=\frac{{\alpha^2}}{\alpha_G}=f_P^{-2}\)

Applying this to dark energy density 

\(u_{DE}=\dfrac{\Lambda}{\kappa}=\frac{A^2_{\Lambda}}{8\pi\;B_P}=\frac{u_P}{8\;\pi}\dfrac{\nu_{\Lambda}^{2}}{\nu_p^{2}}=\frac{u_P}{8\;\pi}\;6.8*10^{-122}=5.3*10^{-10}\;\frac{J}{m^3}\)
------

answered Aug 3, 2022 by Hyperthought (5 points) [ no revision ]

Your answer

Please use answers only to (at least partly) answer questions. To comment, discuss, or ask for clarification, leave a comment instead.
To mask links under text, please type your text, highlight it, and click the "link" button. You can then enter your link URL.
Please consult the FAQ for as to how to format your post.
This is the answer box; if you want to write a comment instead, please use the 'add comment' button.
Live preview (may slow down editor)   Preview
Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
If you are a human please identify the position of the character covered by the symbol $\varnothing$ in the following word:
$\varnothing\hbar$ysicsOverflow
Then drag the red bullet below over the corresponding character of our banner. When you drop it there, the bullet changes to green (on slow internet connections after a few seconds).
Please complete the anti-spam verification




user contributions licensed under cc by-sa 3.0 with attribution required

Your rights
...