Quantcast
  • Register
PhysicsOverflow is a next-generation academic platform for physicists and astronomers, including a community peer review system and a postgraduate-level discussion forum analogous to MathOverflow.

Welcome to PhysicsOverflow! PhysicsOverflow is an open platform for community peer review and graduate-level Physics discussion.

Please help promote PhysicsOverflow ads elsewhere if you like it.

News

PO is now at the Physics Department of Bielefeld University!

New printer friendly PO pages!

Migration to Bielefeld University was successful!

Please vote for this year's PhysicsOverflow ads!

Please do help out in categorising submissions. Submit a paper to PhysicsOverflow!

... see more

Tools for paper authors

Submit paper
Claim Paper Authorship

Tools for SE users

Search User
Reclaim SE Account
Request Account Merger
Nativise imported posts
Claim post (deleted users)
Import SE post

Users whose questions have been imported from Physics Stack Exchange, Theoretical Physics Stack Exchange, or any other Stack Exchange site are kindly requested to reclaim their account and not to register as a new user.

Public \(\beta\) tools

Report a bug with a feature
Request a new functionality
404 page design
Send feedback

Attributions

(propose a free ad)

Site Statistics

205 submissions , 163 unreviewed
5,082 questions , 2,232 unanswered
5,353 answers , 22,789 comments
1,470 users with positive rep
820 active unimported users
More ...

  What Parts of QFT Don't Have Classical Analogs?

+ 2 like - 0 dislike
1048 views

We seem to be living in an era of classical analogs. A few examples:

Question: What remaining parts of QFT meaningfully escape any classical analog?

asked Sep 29, 2023 in Theoretical Physics by Matthew D Cory [ no revision ]

Classical and semiclassical methods only capture certain gross effects of the full quantum treatment.

In particular, discrete spectra need quantum physics for their explanation.

Radiative corrections and parametric downconversion are not described by sclassical tochastic electrodynamics.

Certainly. But I detect a form of circular reasoning because there's no well-defined idea of measurement. To invert the point, how can we explain the continuous spectra of so many quantum phenomena as originating from discrete states? There is a kind of triviality revealed by Nyquist-Shannon sampling theory. For instance, imposing a natural UV cutoff on the spectrum of the Laplacian (or d'Alembertian) operator makes physical fields "bandlimited", allowing them to be perfectly reconstructed from samples on a lattice using sampling theory. This establishes an equivalence between continuous and discrete representations. A signal theory perspective provides a classical explanation for how continuous spectra can turn into discrete spectra while preserving the underlying continuity. The discrete samples arise from limitations on measurement precision and frequency bandwidth, not an inherent quantum discreteness. 

Aside: I come from a math background, looking into an "intentional" setting for proof theory and the reflection principles of ordinal analysis to address the halting problem (hint: the redundant metaphysics of metamathematics got everybody off course). In time, I became a big fan of E.T. Jaynes and his attitude towards measure theory (see the Mycielski-Sierpiński Division Paradox) and the Church of Limitology. I'm actually a variety of formalist ultrafinitist (CAS does any given math and neurons need only GLMs), so I have no hostility to discrete accounts of nature. I have come to see that continuity is the degenerate case of discrete analysis, as Doron Zeilberger astutely remarked. It has nothing to do with "infinite discreteness” but emerges from simplifying symmetries. Like with motion paradoxes, mathematical ideas of continuity really don't say anything definitive about the continuum of nature. I don't pretend to know the ultimate granularity of nature. However, I think insights from signal analysis should make us more reluctant to say we've hit bottom.

Your point about Stokes is insightful. You might remember that the Riemann–Silberstein formulation of electromagnetism was using the Shrodinger equation well before Shrodinger used it for quantum mechanics.

Your answer

Please use answers only to (at least partly) answer questions. To comment, discuss, or ask for clarification, leave a comment instead.
To mask links under text, please type your text, highlight it, and click the "link" button. You can then enter your link URL.
Please consult the FAQ for as to how to format your post.
This is the answer box; if you want to write a comment instead, please use the 'add comment' button.
Live preview (may slow down editor)   Preview
Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
If you are a human please identify the position of the character covered by the symbol $\varnothing$ in the following word:
p$\hbar$y$\varnothing$icsOverflow
Then drag the red bullet below over the corresponding character of our banner. When you drop it there, the bullet changes to green (on slow internet connections after a few seconds).
Please complete the anti-spam verification




user contributions licensed under cc by-sa 3.0 with attribution required

Your rights
...