Quantcast
  • Register
PhysicsOverflow is a next-generation academic platform for physicists and astronomers, including a community peer review system and a postgraduate-level discussion forum analogous to MathOverflow.

Welcome to PhysicsOverflow! PhysicsOverflow is an open platform for community peer review and graduate-level Physics discussion.

Please help promote PhysicsOverflow ads elsewhere if you like it.

News

PO is now at the Physics Department of Bielefeld University!

New printer friendly PO pages!

Migration to Bielefeld University was successful!

Please vote for this year's PhysicsOverflow ads!

Please do help out in categorising submissions. Submit a paper to PhysicsOverflow!

... see more

Tools for paper authors

Submit paper
Claim Paper Authorship

Tools for SE users

Search User
Reclaim SE Account
Request Account Merger
Nativise imported posts
Claim post (deleted users)
Import SE post

Users whose questions have been imported from Physics Stack Exchange, Theoretical Physics Stack Exchange, or any other Stack Exchange site are kindly requested to reclaim their account and not to register as a new user.

Public \(\beta\) tools

Report a bug with a feature
Request a new functionality
404 page design
Send feedback

Attributions

(propose a free ad)

Site Statistics

205 submissions , 163 unreviewed
5,082 questions , 2,232 unanswered
5,353 answers , 22,789 comments
1,470 users with positive rep
820 active unimported users
More ...

  How to verify gauge invariance of an amplitude

+ 0 like - 0 dislike
1597 views

I have calculated a tree level amplitude for Compton scattering (${e\left(p\right)+\gamma\left(k\right)\to e\left(p\prime\right)+\gamma\left(k\prime\right)}$):

$${ i\mathcal{M}=M_{\mu\nu}\epsilon^{*\mu}\left(k\prime\right)\epsilon^{\nu}\left(k\right)\textrm{.} }$$

How should I go about trying to verify that it is gauge invariant?

This post imported from StackExchange Physics at 2014-04-15 16:46 (UCT), posted by SE-user d3pd
asked Sep 5, 2013 in Theoretical Physics by d3pd (0 points) [ no revision ]

1 Answer

+ 1 like - 0 dislike

Don't forget that the polarization tensors depend on the gauge choice via reference vectors (call them $q$, $q'$) Now you have to check what happen when you chance the reference vectors from $q, q'$ to some new vectors $r,r'$. The change of the vectors will lead to the new polarization vectors aquire a term proportional to its momentum $p$. $$\epsilon(p,r)^\mu \sim \epsilon(p,q)^\mu+p^\mu$$

The contraction of the last term with $M_{\mu\nu}$ vanishes, i.e. you have shown gauge invariance. Do you also have to show that $M_{\mu\nu}$ contracted into one of its momenta vanishes?

This post imported from StackExchange Physics at 2014-04-15 16:46 (UCT), posted by SE-user A friendly helper
answered Sep 5, 2013 by A friendly helper (320 points) [ no revision ]
Yes, that makes sense. Thanks muchly for your help.

This post imported from StackExchange Physics at 2014-04-15 16:46 (UCT), posted by SE-user d3pd

Your answer

Please use answers only to (at least partly) answer questions. To comment, discuss, or ask for clarification, leave a comment instead.
To mask links under text, please type your text, highlight it, and click the "link" button. You can then enter your link URL.
Please consult the FAQ for as to how to format your post.
This is the answer box; if you want to write a comment instead, please use the 'add comment' button.
Live preview (may slow down editor)   Preview
Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
If you are a human please identify the position of the character covered by the symbol $\varnothing$ in the following word:
$\varnothing\hbar$ysicsOverflow
Then drag the red bullet below over the corresponding character of our banner. When you drop it there, the bullet changes to green (on slow internet connections after a few seconds).
Please complete the anti-spam verification




user contributions licensed under cc by-sa 3.0 with attribution required

Your rights
...