I'm trying to prove that, under the gauge transformation Aμ→A′μ=g−1Aμg+g−1∂μg,
the non-abelian Chern-Simons Lagrangian density:
LCS=κϵμνρtr(Aμ∂νAρ+23AμAνAρ)
becomes:
LCS ⟶ LCS−κϵμνρ∂μtr(∂νgg−1Aρ)−κ3ϵμνρtr(g−1∂μgg−1∂νgg−1∂ρg)
as stated in Gerald V. Dunne's lecture notes 'Aspects of Chern-Simons Theory' pages 15-16.
The second term in the last equation can be disregarded as it's a total derivative and the third term can be shown to be some integer multiple of 2π provided κ is an integer.
Now I understand that gauge invariance of the CS-term can be proven using some clever reasoning (see: Gauge invariant Chern-Simons Lagrangian). However I want to show how we can arrive at the second equation above using the `brute force' method of plugging in the gauge transformed vector field into the Lagrangian. Unfortunately I get stuck with a large number of terms that I'm not sure how to combine or cancel.
Does anyone know of a source that goes through the above calculation in more detail, or does anyone have any tips for how to proceed. I've done a rather extensive search and can't find any sources that show some of the steps. I already tried using the cyclic properties of the trace and the cancelation of any symmetric term with the anti-symmetric ϵμνρ.
Thank you in advance for any suggestions.
This post imported from StackExchange Physics at 2014-06-29 09:37 (UCT), posted by SE-user Gary B