Quantcast
  • Register
PhysicsOverflow is a next-generation academic platform for physicists and astronomers, including a community peer review system and a postgraduate-level discussion forum analogous to MathOverflow.

Welcome to PhysicsOverflow! PhysicsOverflow is an open platform for community peer review and graduate-level Physics discussion.

Please help promote PhysicsOverflow ads elsewhere if you like it.

News

PO is now at the Physics Department of Bielefeld University!

New printer friendly PO pages!

Migration to Bielefeld University was successful!

Please vote for this year's PhysicsOverflow ads!

Please do help out in categorising submissions. Submit a paper to PhysicsOverflow!

... see more

Tools for paper authors

Submit paper
Claim Paper Authorship

Tools for SE users

Search User
Reclaim SE Account
Request Account Merger
Nativise imported posts
Claim post (deleted users)
Import SE post

Users whose questions have been imported from Physics Stack Exchange, Theoretical Physics Stack Exchange, or any other Stack Exchange site are kindly requested to reclaim their account and not to register as a new user.

Public \(\beta\) tools

Report a bug with a feature
Request a new functionality
404 page design
Send feedback

Attributions

(propose a free ad)

Site Statistics

205 submissions , 163 unreviewed
5,082 questions , 2,232 unanswered
5,353 answers , 22,789 comments
1,470 users with positive rep
820 active unimported users
More ...

  What is 'heterotic string compactification'?

+ 3 like - 0 dislike
698 views

I've read that some exceptional groups arises in the context of 'heterotic string compactification'.

Could someone explain (to a person studying physics but who doesn't know string theory) what heterotic string compactification involves and what why exceptional groups have to do with it?

This post imported from StackExchange Physics at 2014-06-15 16:46 (UCT), posted by SE-user Anne O'Nyme
asked Jun 13, 2014 in Theoretical Physics by Anne O'Nyme (175 points) [ no revision ]

1 Answer

+ 3 like - 0 dislike

That's an easy question. I'll assume in this answer, for the purposes of PhysicsOverflow, that you have at least a basic knowledge of quantum field theory.

Heterotic strings, as their name suggests, arise as a "hybrid" of a bosonic string and a Type II superstring. This "hybrid" is formed by the left-movers of the bosonic string and the right-movers of the Type II string.

Now, Bosonic strings are consistent only in 26-dimensional spacetime. The consistency argument depends on the type of quantisation that you use. If you use canonical quantisation to quantise your bosonic string, then one needs a central charge of 26 to cancel out the negative-norm-square states from the theory. If you use Light Cone Gauge quantisation, 26 is the only spacetime dimension in which Lorentz Invariance is respected in bosonic string theory. Generally, you need a 26-dimensional spacetime to get rid of "conformal anomaly". Even if you are ready (which you shouldn't be) to accept negative-norm-square ghost states or the lack of Lorentz Invariance, you need a dimension of 26 to ensure that the different quantisation methods are consistent with one another in string theory.

On the other hand, Type II superstrings are only consistent in 10-dimensional spacetime, for similar reasons to the bosonic string. But you obviously can't have the left-movers living in 26-dimensional spacetime with the right-movers living in 10-dimensional spacetime!

The solution is to compactify the spacetime of the left-movers on a 16-dimensional lattice. This means that you make 16 of the dimensions of the left-movers' spacetime infinitesimally small. It happens to be (see notes) that this lattice needs to be even and unimodular. There are only 2 lattices that satisfy this. Namely, \(\frac{\operatorname{Spin}\left(32\right)}{\mathbb{Z}_2}\) and \(\left(E_8\right)^2\). The second is the cartesian product of an exceptional group with itself.

Notes

For an explanation as to why the lattice must be unimodular and even, see this article and this answer.

answered Jun 16, 2014 by dimension10 (1,985 points) [ no revision ]
Concise explanation +1, I will ensure that the OP sees it ...

Your answer

Please use answers only to (at least partly) answer questions. To comment, discuss, or ask for clarification, leave a comment instead.
To mask links under text, please type your text, highlight it, and click the "link" button. You can then enter your link URL.
Please consult the FAQ for as to how to format your post.
This is the answer box; if you want to write a comment instead, please use the 'add comment' button.
Live preview (may slow down editor)   Preview
Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
If you are a human please identify the position of the character covered by the symbol $\varnothing$ in the following word:
p$\hbar$ysicsOve$\varnothing$flow
Then drag the red bullet below over the corresponding character of our banner. When you drop it there, the bullet changes to green (on slow internet connections after a few seconds).
Please complete the anti-spam verification




user contributions licensed under cc by-sa 3.0 with attribution required

Your rights
...