Register

Adv. Query

Q&A (4871)

Reviews (203)

Open problems (47)
Meta (439)

Site Statistics

205 submissions , 163 unreviewed
5,082 questions , 2,232 unanswered
5,353 answers , 22,789 comments
1,470 users with positive rep
820 active unimported users
More ...

How do I find the time needed for an object to travel a certain amount of distance if I have the distance it traveled, the mass of the object, and it was pulled with a constant force?

3352 views

Is there any equation to find the time taken for an object to travel a certain distance if I am given the distance the object traveled, the mass of the object, and a constant force that was used to pull the object? For example, if an object with a mass of 1 kg travels a distance of 100 meters with a constant force of 9.81 newtons without stopping, is there a way to calculate the time it took the object to travel the distance of 100 meters?

Closed as per community consensus as the post is not grad-level

asked Jul 3, 2017 in Closed Questions by efake2002 (-10 points) [ no revision ]
recategorized Jul 4, 2017 by dimension10

Most voted comments show all comments

@Dilaton

commented Jul 3, 2017 by efake2002 (-10 points) [ no revision ]

@efake2002 I understand, but PO is not for this level of questions.

You can try PhysicsForums or the relatively new Physics Problems Q&A to get help with your question.

commented Jul 3, 2017 by Dilaton (6,240 points) [ no revision ]

@Dilaton Please answer sir. I'll close this thread myself. Just provide me the equation. I have an assignment due soon. Please! Just give me an equation. Thanks in advance.

commented Jul 3, 2017 by efake2002 (-10 points) [ no revision ]

This is a high level question. I've already tried those forums and they have requested me to post the question in this website. Please sir. Just answer the question and I'll get outta here.@Dilaton

commented Jul 3, 2017 by efake2002 (-10 points) [ no revision ]

@Dilaton Are u there? Please answer man. It's urgent

commented Jul 3, 2017 by efake2002 (-10 points) [ no revision ]

Most recent comments show all comments

Someone please answer!!

commented Jul 3, 2017 by efake2002 (-10 points) [ no revision ]

This is not graduate-level. 500+ rep users please up(down)vote my closevote if you (dis)agree here.

commented Jul 3, 2017 by Dilaton (6,240 points) [ revision history ]

Your comment on this question:

To answer, leave an answer instead. Comments are usually for non-answers.
To mask links under text, please type your text, highlight it, and click the "link" button. You can then enter your link URL.
To alert a user, please use the "@" command and remove spaces from the username, example, the user "John Doe" should be pinged as "@JohnDoe", while the user "Johndoe" should be pinged as "@Johndoe". The post author is always automatically pinged (unless you are the post author).
Please consult the FAQ for as to how to format your post.

Live preview (may slow down editor) Preview

Your name to display (optional):

Email me at this address if a comment is added after mine:

Privacy: Your email address will only be used for sending these notifications.

Anti-spam verification:

If you are a human please identify the position of the character covered by the symbol $\varnothing$ in the following word:
p$\hbar$ysi$\varnothing$sOverflow
Then drag the red bullet below over the corresponding character of our banner. When you drop it there, the bullet changes to green (on slow internet connections after a few seconds).

Please complete the anti-spam verification

1 Answer

Yes, there is such an equation, but it involves also the initial velocity, which is unknown, according to you. So the answer is uncertain without the initial velocity.

The equation itself is derived from the distance equation: $L(t)=L(0)+V_0\times t + F\times t^2/2m$. So your time is expressed via $D=L-L(0)$, $V_0$, and $F$. You just solve the square equation and find $t_{1,2}(D,V_0,F,m)$.

answered Jul 4, 2017 by Vladimir Kalitvianski (102 points) [ revision history ]
edited Jul 4, 2017 by Vladimir Kalitvianski

Such basic high-school level questions are off-topic for PO and should therefore not get answered here.

commented Jul 4, 2017 by Dilaton (6,240 points) [ revision history ]

@Dilaton: I agree and I think my answer will prevent it from being a permanent top question on PhysicsOverflow.

commented Jul 4, 2017 by Vladimir Kalitvianski (102 points) [ no revision ]

@Vladimir ok, I understand your motivation.

But it is still better to not answer such questions. Otherwise we will get more and more of them which would reduce the value of the site for those interested in high-level discussions.

commented Jul 4, 2017 by Dilaton (6,240 points) [ no revision ]

Your comment on this answer:

To answer, leave an answer instead. Comments are usually for non-answers.
To mask links under text, please type your text, highlight it, and click the "link" button. You can then enter your link URL.
To alert a user, please use the "@" command and remove spaces from the username, example, the user "John Doe" should be pinged as "@JohnDoe", while the user "Johndoe" should be pinged as "@Johndoe". The post author is always automatically pinged (unless you are the post author).
Please consult the FAQ for as to how to format your post.

Live preview (may slow down editor) Preview

Your name to display (optional):

Email me at this address if a comment is added after mine:

Privacy: Your email address will only be used for sending these notifications.

Anti-spam verification:

[captcha placeholder]

Please complete the anti-spam verification

user contributions licensed under cc by-sa 3.0 with attribution required

Your rights

...