I want to do the following path integral.
Z=∫DxeiS[˙x]
The action only denpends on ˙x. For some reason, I want to replace the integral measure Dx by D˙x.
So I have
Z=∫D˙xDet(δxδ˙x)eiS[˙x].
The variable x is related with ˙x via the linear transformation
x(t)=∫t0˙x(s)ds,
which implies
Det(δxδ˙x)≡1.
Am I correct in the above derivation?