# Supergravity and Gamma Matrices

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On page 101 of Freedman and Van Proeyen's book on Supergravity they find the propagator of the gravitino, however I'm not sure how to work through the steps in (5.30), and hints or answers would be great help.

It begins with the equation of motion

$$\gamma^{\mu\nu\rho}\partial_\nu\Psi_\rho=J^\mu\tag{5.18}$$

and an ansatz solution of the form,

$$\Psi_\mu(x)=-\int d^DyS_{\mu\nu}(x-y)J^\nu(y).\tag{5.26}$$

Subbing this into the equation of motion gives,

$$i\gamma^{\mu\sigma\rho}p_\sigma S_{\rho\nu}(p)=i{\delta}{^\mu_\nu}-ip_\nu\Omega^\mu(p) \tag{5.28}$$

in momentum space where $$\Omega^\mu$$ is a pure gauge term and contains all the dependence on $$p_\mu$$ only. They then go on to produce an ansatz for this equation of the form,

$$\require{cancel}iS_{\rho\nu}(p)=A(p^2)\eta_\rho\nu\cancel{p}+B(p^2)\gamma_\rho\cancel{p}\gamma_\nu\tag{5.29}$$

which they then sub into the LHS of $$(5.28)$$ to obtain the following,

\begin{align} i\gamma^{\mu\sigma\rho}p_\sigma S_{\rho\nu}(p)&=A\gamma^{\mu\sigma}_\nu\cancel{p}p_\sigma+(D-2)B\gamma^{\mu\sigma}\cancel{p}\gamma_\nu p_\sigma\\ &=A(p^\mu\gamma^\sigma_\nu-p^\sigma\gamma^\mu_\nu)p_\sigma+(D-2)B(-p^\mu\gamma^\sigma+p^\sigma\gamma^\mu)\gamma_\nu p_\sigma+...\\ &=[A-(D-2)B](p^\mu\gamma^\sigma_\nu-p^\sigma\gamma^\mu_\nu)p_\sigma+(D-2)Bp^2\delta^\mu_\nu+... \end{align}\tag{5.30}

where the ... represents terms that are proportional to the vector $$p_\nu$$. I'm just unsure of how to go from the first to second and then to the third line of the above aligned equations.

This post imported from StackExchange Physics at 2019-07-09 21:53 (UTC), posted by SE-user huntercallum
Undo the slashes as $\gamma_\kappa p^\kappa$. Do the simpler version of their (3.21), with just one γ hitting on the right. The B term is even simpler: symmetrize and antisymmetric the two γ s involved. They really expect you to master the technique if you are to trust them.
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