# On-shell action in asymptotically AdS space

+ 4 like - 0 dislike
260 views

Consider a field theory coupled with gravity described by the action:

$S=\int d^Dx \sqrt{-g} \left( \mathcal{R}-\Lambda+\mathcal{L}_m[\phi] \right)$,

with the requirement that g must be asymptotically AdS.

Usually in AdS/CFT correspondence the action evaluated on-shell reduces to a purely boundary term.

Is there a general formula to express this boundary term?

This post imported from StackExchange Physics at 2014-03-07 13:46 (UCT), posted by SE-user Andrea Amoretti
If you're fixing the boundary to be AdS, then what is there left to vary at the boundary? Or are you asking if there is a way to express the above action as $\oint d^{D-1}x \sqrt{|g_{ind}|}(stuff) + \int d^{D}x\sqrt{-g}\mathcal{L}_{m}$?

This post imported from StackExchange Physics at 2014-03-07 13:46 (UCT), posted by SE-user Jerry Schirmer
Yes, usually in holography you make an ansatz on the metric and on the fields and then you evaluate the action on the equations of motion. Typically the action reduces to a purely surface term, since the bulk term vanishes due to the equations of motion. I'm asking if there are general rule to express this boundary term without compute case by case the on shell action

This post imported from StackExchange Physics at 2014-03-07 13:46 (UCT), posted by SE-user Andrea Amoretti
This happens somewhat generically in general relativity, due to the diffeomorphism invariance, though the relativity community typically will discuss this in terms of constraints and evolution equations. Any good discussion on a 3+1 formalism will show that the Hilbert action is equivalent to a sum of constraints that are satisfied on the boundary of your spacetime evolution.

This post imported from StackExchange Physics at 2014-03-07 13:46 (UCT), posted by SE-user Jerry Schirmer
 Please use answers only to (at least partly) answer questions. To comment, discuss, or ask for clarification, leave a comment instead. To mask links under text, please type your text, highlight it, and click the "link" button. You can then enter your link URL. Please consult the FAQ for as to how to format your post. This is the answer box; if you want to write a comment instead, please use the 'add comment' button. Live preview (may slow down editor)   Preview Your name to display (optional): Email me at this address if my answer is selected or commented on: Privacy: Your email address will only be used for sending these notifications. Anti-spam verification: If you are a human please identify the position of the character covered by the symbol $\varnothing$ in the following word:p$\hbar$y$\varnothing$icsOverflowThen drag the red bullet below over the corresponding character of our banner. When you drop it there, the bullet changes to green (on slow internet connections after a few seconds). To avoid this verification in future, please log in or register.