When you write the Dirac equation in a curved spacetime, in the context of General Relativity (which allows curvature, but not torsion) , you have a spin connection :
∇μψ=(∂μ−i4ωIJμσIJ)ψ
Now, the Einstein-Cartan theory is not General Relativity, because it allows curvature, but also torsion, which is proportionnal to your term κ.
So, it turns, that, in presence of torsion (κ), everything happens as if there was a Lagrangian with a quadratic term, so the equation of movement has a cubic term (see for instance, this Ref, formula 16 for the torsion, and formula 31 for the Dirac equation.
[EDIT]
Due to OP comments, some precisions :
(Always working with the same Ref):
∇μψ, is the covariant derivative for a spinor in general relativity, that is without torsion. This means that the Dirac equation in general relativity is (iγμ∇μ−m)ψ=0. But it is no more true with a space-time with torsion, so it is better to use an other notation Dμ if you want to write a Dirac equation like (iγμDμ−m)ψ=0. The quartic term (in ψ) for Rab (formula 30), or the quadratic term in Ta (formula 29), which lead to the cubic term for the Dirac equation (formula 31), come from the coupled Euler-Lagrange equations 15,16. For instance, you see, in formula 4, that the connection has a supplementary term Kab (contorsion), which is linked to the torsion (formula 6), which is itself quadratic in the ψ (formula 29). So, in some way, you may simply consider this supplementary connection, if you remember where connection appears in a "derivative". Yes κ is the gravitational constant, see formula 9. Now, you may look, in this ref, that the torsion (defined in formula 2), in the Einstein-Cartan model (formulae 8,9), is proportionnal to κ (formula 16)
This post imported from StackExchange Physics at 2014-03-07 16:43 (UCT), posted by SE-user Trimok