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  Breaking of Lorentz invariance

+ 6 like - 0 dislike
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Thinking about the concept of symmetry breaking led me to the following question: Let's say that I have a theory described by a Lorentz invariant Lagrangian, and the true vacuum of the theory is not invariant under Lorentz transformation, will there be massless Goldstone bosons (or fermions) similar to the breaking of a gauge symmetry? How would it be different from this kind of symmetry breaking? What would be some phenomenological consequences? Or would it be stupid (for some reasons) to look at this kind of vacuum from the beginning?

Thanks.

This post imported from StackExchange Physics at 2014-05-01 12:15 (UCT), posted by SE-user toot
asked May 18, 2012 in Theoretical Physics by toot (445 points) [ no revision ]
People definitely investigate this sort of thing.There will be goldstone bosons in general. Other than that its outside my area. See arxiv.org/pdf/1004.5596.pdf

This post imported from StackExchange Physics at 2014-05-01 12:15 (UCT), posted by SE-user DJBunk
commented May 18, 2012 by DJBunk (80 points) [ no revision ]

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