Quantcast
  • Register
PhysicsOverflow is a next-generation academic platform for physicists and astronomers, including a community peer review system and a postgraduate-level discussion forum analogous to MathOverflow.

Welcome to PhysicsOverflow! PhysicsOverflow is an open platform for community peer review and graduate-level Physics discussion.

Please help promote PhysicsOverflow ads elsewhere if you like it.

News

PO is now at the Physics Department of Bielefeld University!

New printer friendly PO pages!

Migration to Bielefeld University was successful!

Please vote for this year's PhysicsOverflow ads!

Please do help out in categorising submissions. Submit a paper to PhysicsOverflow!

... see more

Tools for paper authors

Submit paper
Claim Paper Authorship

Tools for SE users

Search User
Reclaim SE Account
Request Account Merger
Nativise imported posts
Claim post (deleted users)
Import SE post

Users whose questions have been imported from Physics Stack Exchange, Theoretical Physics Stack Exchange, or any other Stack Exchange site are kindly requested to reclaim their account and not to register as a new user.

Public \(\beta\) tools

Report a bug with a feature
Request a new functionality
404 page design
Send feedback

Attributions

(propose a free ad)

Site Statistics

205 submissions , 163 unreviewed
5,082 questions , 2,232 unanswered
5,353 answers , 22,789 comments
1,470 users with positive rep
820 active unimported users
More ...

  Homeomorphism between the space of all Ashtekar connections and spacetime?

+ 3 like - 0 dislike
722 views

Excerpt from an essay of mine:

Let $\Psi(\varsigma)$ be the wavefunction in the loop representation, where $\varsigma:[0,1]\to\mathcal{M}$, where $\mathcal{M}$ is spacetime. Then, let $\mathcal{A}$ be the Ashtekar connection and $\mathcal{W}_\varsigma[\mathcal{A}]$ be the Wilson loop of the connection $\mathcal{A}$. Give the connection the action $S[\mathcal{A}]=\oint_\varsigma -i\mathcal{A}$. One then has \begin{multline} \Psi(\varsigma)\Psi(\varsigma_{1})=\langle \mathcal{W}_\varsigma[\mathcal{A}]\mathcal{W}_{\varsigma_1}[\mathcal{A}_1]\rangle=\langle0| \mathcal{W}_\varsigma[\mathcal{A}]\mathcal{W}_{\varsigma_1}[\mathcal{A}_1]|0\rangle=\\ \int D\mathcal{A}\int D\mathcal{A}\left(\operatorname{Tr}\left(\mathcal{P}\exp\left(\oint_\varsigma -i\mathcal{A}\right)\right)\right)^2\mathcal{W}_\varsigma[\mathcal{A}]\mathcal{W}_{\varsigma_{1}}[\mathcal{A}_1] \end{multline} This, as is written in the equation, has the form of a 2 Wilson loop correlation function. For simplicity, we assume an interaction of the form $(\mathcal{W}_\varsigma[\mathcal{A}])^2$. Let $|\Theta\rangle$ be the ground state of loop quantum gravity. Then, one has the S-matrix elements of loop quantum gravity in the space of all Ashtekar connections as \begin{equation} \langle\Theta|\mathcal{W}_\varsigma[\mathcal{A}]\mathcal{W}_{\varsigma_1}[\mathcal{A}_1]|\Theta\rangle=\sum^\infty_{n=0}(-i\lambda)^n\int\mathrm{d}^4x_n\langle0|\mathcal{W}_\varsigma[\mathcal{A}]\mathcal{W}_{\varsigma_1}[\mathcal{A}_1]\prod^n_{j=1}(\mathcal{W}_{\varsigma}[\mathcal{A}^j])^2|0\rangle=\sum^\infty_{n=0}\Theta^{(n)} \end{equation} Here, $\lambda$ is the coupling constant of LQG. $\mathcal{A}^j$ stands for different connections, i.e., $\mathcal{A}^1=\mathcal{B},\mathcal{A}^2=\mathcal{C}$, e.t.c. The Feynman diagrams come from $\langle\Theta|\mathcal{W}_\varsigma[\mathcal{A}]\mathcal{W}_{\varsigma_1}[\mathcal{A}_1]|\Theta\rangle=D_F(\mathcal{A},\mathcal{A}_1)+\mbox{\emph{all possible contractions}}$. Here, ``all possible contractions'' means all possible pairings between the connections of which the Wilson loop is a functional. We choose to study only a limited number of contractions.

We write two contractions for $\Theta^{(1)}$: 1)$D_F(\mathcal{A},\mathcal{A}_1)\left(D_F(\mathcal{B,B})\right)^2$

2) $D_F(\mathcal{A,B})D_F(\mathcal{A}_1,\mathcal{B})D_F(\mathcal{B,B})$

We write four contractions for $\Theta^{(2)}$: 1) $D_F(\mathcal{A,A}_1)\left(D_F(\mathcal{B,B})\right)^2D_F(\mathcal{B,C})\left(D_F(\mathcal{C,C})\right)^2$

2) $D_F(\mathcal{A},\mathcal{B})D_F(\mathcal{A}_1,\mathcal{B})D_F(\mathcal{B,B})D_F(\mathcal{B,C})\left(D_F(\mathcal{C,C})\right)^2$

3)$D_F(\mathcal{A},\mathcal{B})D_F(\mathcal{A}_1,\mathcal{C})\left(D_F(\mathcal{B,B})\right)^2\left(D_F(\mathcal{C,C})\right)^2$

4) $D_F(\mathcal{A,C})D_F(\mathcal{A}_1,\mathcal{C})\left(D_F(\mathcal{B,B})\right)^2D_F(\mathcal{B,C})D_F(\mathcal{C,C})$

Note that this list does not contain every single propagator.

In the space of all Ashtekar connections (which is a subset of the space of all principal connections of spacetime), the interactions of LQG are given by finding out all possible contractions of the Feynman propagators and drawing diagrams in the space of all Ashtekar connections.

My question thus is: Is it possible to somehow find a homeomorphism between the space of all Ashtekar connections and spacetime (so that the interactions of LQG can be formulated on spacetime itself)?


This post imported from StackExchange Physics at 2015-10-20 21:59 (UTC), posted by SE-user Sanath Devalapurkar

asked Jan 12, 2014 in Theoretical Physics by Sanath Devalapurkar (25 points) [ revision history ]
edited Oct 20, 2015 by Dilaton
The short answer is: no. Why? We have two different topological invariants -- the dimension of the "space of all Ashtekar connections" is infinite-dimensional, whereas spacetime is 4-dimensional. And $4\neq\infty$.

This post imported from StackExchange Physics at 2015-10-20 21:59 (UTC), posted by SE-user Alex Nelson

Your answer

Please use answers only to (at least partly) answer questions. To comment, discuss, or ask for clarification, leave a comment instead.
To mask links under text, please type your text, highlight it, and click the "link" button. You can then enter your link URL.
Please consult the FAQ for as to how to format your post.
This is the answer box; if you want to write a comment instead, please use the 'add comment' button.
Live preview (may slow down editor)   Preview
Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
If you are a human please identify the position of the character covered by the symbol $\varnothing$ in the following word:
p$\hbar$ysi$\varnothing$sOverflow
Then drag the red bullet below over the corresponding character of our banner. When you drop it there, the bullet changes to green (on slow internet connections after a few seconds).
Please complete the anti-spam verification




user contributions licensed under cc by-sa 3.0 with attribution required

Your rights
...