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  Why is the total capacitance for the CPB-circuit a sum

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In this document  (p.6 eqn. 2.1) and also in the general literature for the the basic Cooper pair box circuit the total capacitance \(C_\Sigma\) is the sum of the gate-capacitance \(C_g\) and the capacitance of the Josephson-Junction \(C_J\). Why is that the case? As far as I can see the elements are connected in series and thus only the inverses add up to the inverse of the total capacitance. What am I missing? Are  the capacitances actually connected in parallel? If so can somebody explain why they are considered in parallel, because I don't understand it.

Thanks in advance!

asked Jun 25, 2019 in Chat by anonymous [ no revision ]
recategorized Jun 28, 2019 by Dilaton

the junction is not a serial circuit. The 2 capacitors of the pass filters ( meaning 99.99% of the total junction capacitance ) are embeded in // circuits. Very interesting question when linked to a scale description... Perhaps to move to the chat forum?

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