# How exactly are Calabi-Yau compactifications done?

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To compactify 2 open dimensions to a torus, the method of identification written down for this example as

$$(x,y) \sim (x+2\pi R,y)$$

$$(x,y) \sim (x, y+2\pi R)$$

can be applied.

What are the methods to compactify 6 open dimensions to a Calaby-Yau manifold and how exactly do these methods work?

asked Jul 14, 2013
retagged Apr 19, 2014
Interesting question. When I first heard of compactifications on CY, I thought such identifications would be trivial, but I realised it isn't exactly trivial... .

This post imported from StackExchange Physics at 2014-03-09 16:15 (UCT), posted by SE-user Dimensio1n0

## 1 Answer

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What you wrote down is the quotient of the 2-dimensional translation group by a discrete subgroup. But by far not every closed manifold arises as a quotient of groups this way.

One should be aware that the term "compactification" in physics is used not so much to refer to what in mathematics is called compactification of non-compact spaces. For instace one-point compactification in the mathematical sense turns the real line line into the circle. (However it also turns the plane into the 2-sphere, not into the torus.)

Instead, what is meant by "compactification" in physics is that you just choose a closed (and hence compact) manifold $Q$, then choose spacetime $X$ to be a $Q$-fiber bundle over space base space (often assumed to be just a product $X = Q \times Y$), and then describe the Kaluza-Klein mechanism for passing from physics on $X = Q \times Y$ to effective physics on just $Y$.

In particular for Calabi-Yau "compactifications" you just choose $Q$ to be a Calabi-Yau manifold, and then consider the Kaluza-Klein mechanism on spacetimes which are $Q$-fiber bundles. You don't actually obtain these spacetimes as compactifications of non-compact spacetimes in the sense of mathematics.

(Well one could consider that problem, but this is not what is generally meant by "compactification" in physics.)

This post imported from StackExchange Physics at 2014-03-09 16:15 (UCT), posted by SE-user Urs Schreiber
answered Jul 14, 2013 by (6,025 points)
Thanks for this nice clarification, going to follow the links now :-)

This post imported from StackExchange Physics at 2014-03-09 16:15 (UCT), posted by SE-user Dilaton
I thought that "$Q$" was the Calabi-Yau manifold, not $Y$. For instance $X_{10} = CY_6 * M_{3,1}$. So I would have thought of $CY$-fiber bundles with a Minkowski base space $M_{3,1}$

This post imported from StackExchange Physics at 2014-03-09 16:15 (UCT), posted by SE-user Trimok

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