Quantcast
  • Register
PhysicsOverflow is a next-generation academic platform for physicists and astronomers, including a community peer review system and a postgraduate-level discussion forum analogous to MathOverflow.

Welcome to PhysicsOverflow! PhysicsOverflow is an open platform for community peer review and graduate-level Physics discussion.

Please help promote PhysicsOverflow ads elsewhere if you like it.

News

PO is now at the Physics Department of Bielefeld University!

New printer friendly PO pages!

Migration to Bielefeld University was successful!

Please vote for this year's PhysicsOverflow ads!

Please do help out in categorising submissions. Submit a paper to PhysicsOverflow!

... see more

Tools for paper authors

Submit paper
Claim Paper Authorship

Tools for SE users

Search User
Reclaim SE Account
Request Account Merger
Nativise imported posts
Claim post (deleted users)
Import SE post

Users whose questions have been imported from Physics Stack Exchange, Theoretical Physics Stack Exchange, or any other Stack Exchange site are kindly requested to reclaim their account and not to register as a new user.

Public \(\beta\) tools

Report a bug with a feature
Request a new functionality
404 page design
Send feedback

Attributions

(propose a free ad)

Site Statistics

205 submissions , 163 unreviewed
5,082 questions , 2,232 unanswered
5,353 answers , 22,789 comments
1,470 users with positive rep
820 active unimported users
More ...

  Possibility of "graviballs"?

+ 6 like - 0 dislike
1467 views

Looking at the relevant wikipedia page, one can read that the graviton should be massless. Is it 100 % certain that it is massless or is there room in any "nonstandard" models for a tiny non-zero mass (which could lead to a similar surprise as the detection of the neutrino oscillation) such that the graviton (if it exists ...) could maybe selfinteract and form something like "graviballs"? (My present knowledge of GR and QFT is at the "Demystified-Level")

asked Jun 4, 2011 in Theoretical Physics by Dilaton (6,240 points) [ revision history ]
This is just a curious question... I`ll retract it if it is too annoying or stupid ;-)

This post imported from StackExchange Physics at 2014-03-11 10:27 (UCT), posted by SE-user Dilaton
I think those are a subgroup of Spaceballs.

This post imported from StackExchange Physics at 2014-03-11 10:27 (UCT), posted by SE-user Georg
Ha ha, maybe ;-) ...

This post imported from StackExchange Physics at 2014-03-11 10:27 (UCT), posted by SE-user Dilaton

2 Answers

+ 5 like - 0 dislike

Gravitons do self-interact. That's because gravity couples to energy-momentum tensor which is non-zero even for massless particles (e.g. consider that gravity influences light). So it's certainly a possibility that they might form a bound state. But you can't see this in a linearized theory of gravity because it is a free theory (similar to electrodynamics). So you'd also have to include higher order curvature terms and quantize those, which would in principle resemble something like chromodynamics (although much harder). It is also not clear whether the theory would be consistent without including the rest of the standard model (and beyond). In any case you'd definitely need some form of quantum gravity to answer this question.

Regarding the first question: there are experimental upper bounds on masses of all massless particles. Obviously it's impossible to distinguish whether something is strictly zero or infinitesimally small. Suffice it to say that all experiments conform to the fact that the masses are zero and there is no theoretical justification whatsoever to consider other models.

This post imported from StackExchange Physics at 2014-03-11 10:27 (UCT), posted by SE-user Marek
answered Jun 4, 2011 by Marek (635 points) [ no revision ]
Thanks Marek for this helpful answer. Now reading that from You I should have known that gravitons interact because they have energy. Lenny Susskind said the same thing about photons in one of his Lectures ... stupid me :-/!

This post imported from StackExchange Physics at 2014-03-11 10:27 (UCT), posted by SE-user Dilaton
And yes, by the graviballs I meant something in analogy to the glueballs in QCD ;-) Would be interesting to know if somebody is doing that ...

This post imported from StackExchange Physics at 2014-03-11 10:27 (UCT), posted by SE-user Dilaton
+ 4 like - 0 dislike

There exists a self-consistent, self-interacting gravitational solitons called "gravitational geon" within general relativity. As Marek said above, gravitational field is non-linear and self-interacting so energy momentum of gravity wave itself will produce bound states. You can read a bit more about it in a following Wiki page:

http://en.wikipedia.org/wiki/Geon_%28physics%29

One important contribution that the Wiki page missed is that you can get a half-integer spin geon from pure gravity, a work by Friedman and Sorkin.

http://prl.aps.org/abstract/PRL/v44/i17/p1100_1

As far as I know there are not much development in quantum mechanical aspect of them.

This post imported from StackExchange Physics at 2014-03-11 10:27 (UCT), posted by SE-user Demian Cho
answered Jun 4, 2011 by Demian Cho (285 points) [ no revision ]
Oh yes these graviational geons are interesting :-). It is just a bit a nuisance that I would have to buy the paper if the second link :-/

This post imported from StackExchange Physics at 2014-03-11 10:27 (UCT), posted by SE-user Dilaton

Your answer

Please use answers only to (at least partly) answer questions. To comment, discuss, or ask for clarification, leave a comment instead.
To mask links under text, please type your text, highlight it, and click the "link" button. You can then enter your link URL.
Please consult the FAQ for as to how to format your post.
This is the answer box; if you want to write a comment instead, please use the 'add comment' button.
Live preview (may slow down editor)   Preview
Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
If you are a human please identify the position of the character covered by the symbol $\varnothing$ in the following word:
p$\varnothing$ysicsOverflow
Then drag the red bullet below over the corresponding character of our banner. When you drop it there, the bullet changes to green (on slow internet connections after a few seconds).
Please complete the anti-spam verification




user contributions licensed under cc by-sa 3.0 with attribution required

Your rights
...