Note that the field ψμα isn't all of the representation (12,12)⊗[(12,0)⊕(0,12)] but only the part of it satisfying γμψμα. This selects the (1,12)⊕(12,1) representation. See Weinberg's QFT Sect. 5.6 for more on this.
We can expand on Sidious Lord's answer. The field Aμ transforms in a inhomogeneous way under Lorentz transformations.
U(Λ)Aμ(x)U(Λ)†=ΛμνAν(x)+∂μΩ(x,Λ).
So, this field isn't technically a 4-vector representation of the Lorentz group. Weinberg treats this in section 5.9. The inhomogenous part cancels out of the field strength.
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