In the same paper that was linked in the question, the authors mentioned the bounds of the TPEs, in Theorem 1.6: Let vC be a classical (N,D,1−lC) TPE, and for 0<p<1, define vQ=pvC+(1−p)δF. Suppose that eA= 1−2(2k)4k/√N>0. Then vQ is a quantum (N,D+1,1−eQ,k) TPE where eQ is greater than or equal to eA/12∗min(peC,1−p)>0. This bound is optimized when p=1/(1+lC) in which case we have eQ is greater than or equal to eAeC/24. This means that any constant degree and gap 2k classical TPE gives a k quantum TPE, with constant gap. If the classical TPE is efficient then the quantum one is too.
From these results, I believe that there is a similar geometric interpretation, except that it is limited when 2k>N, for the quantum expanders.
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