Quantcast
  • Register
PhysicsOverflow is a next-generation academic platform for physicists and astronomers, including a community peer review system and a postgraduate-level discussion forum analogous to MathOverflow.

Welcome to PhysicsOverflow! PhysicsOverflow is an open platform for community peer review and graduate-level Physics discussion.

Please help promote PhysicsOverflow ads elsewhere if you like it.

News

PO is now at the Physics Department of Bielefeld University!

New printer friendly PO pages!

Migration to Bielefeld University was successful!

Please vote for this year's PhysicsOverflow ads!

Please do help out in categorising submissions. Submit a paper to PhysicsOverflow!

... see more

Tools for paper authors

Submit paper
Claim Paper Authorship

Tools for SE users

Search User
Reclaim SE Account
Request Account Merger
Nativise imported posts
Claim post (deleted users)
Import SE post

Users whose questions have been imported from Physics Stack Exchange, Theoretical Physics Stack Exchange, or any other Stack Exchange site are kindly requested to reclaim their account and not to register as a new user.

Public \(\beta\) tools

Report a bug with a feature
Request a new functionality
404 page design
Send feedback

Attributions

(propose a free ad)

Site Statistics

205 submissions , 163 unreviewed
5,082 questions , 2,232 unanswered
5,353 answers , 22,789 comments
1,470 users with positive rep
820 active unimported users
More ...

  Tensor Inverse for Gaussian Quantum Fisher Information

+ 1 like - 0 dislike
261 views

I'm trying to calculate the Quantum Fisher Information (QFI) of a Gaussian state. In this case, I'm following the prescription outlined in this paper https://arxiv.org/abs/1407.7352, which was published here https://link.springer.com/article/10.1140/epjd/e2014-50560-1. In general, my question is about the definition of the tensor inverse for calculating the QFI matrix and how to deal with singular matrices, which seem to come up.

In the Gaussian case, the QFI matrix can be written as $$ \mathfrak{F}_{ij}=\frac{1}{2}(\mathfrak{m}^{-1})_{\mu\nu,\alpha\beta}(\nabla_{\theta_j}\Sigma^{\alpha\beta})(\nabla_{\theta_i}\Sigma^{\mu\nu}) $$

where $\mathfrak{m}$ is defined as $$ \mathfrak{m}=\Sigma\otimes\Sigma+\frac{1}{4}\Omega\otimes\Omega, $$ $\Sigma$ is the covariance matrix of the state, the indices represent the listing of the vector of lowering and raising operators of the state (over the various modes) $a^{\mu}=\left(\hat{a}_1,\hat{a}_1^\dagger,\hat{a}_2,\hat{a}_2^\dagger\right)$, $\theta_i$ is the i-th element of the parameter list, and $\Omega$ is defined by $\Omega=i \sigma_y\oplus i\sigma_y$ where $\sigma_y$ is the Pauli-y matrix.

One part of this is to understand what the "inverse" of the tensor $\mathfrak{m}$ should be. To my knowledge, the authors seem to define it as below: $$ (\mathfrak{m}^{-1})_{ijkl}\mathfrak{m}_{klmn}=\delta_{im}\delta_{jn} $$ So that we can arrive at their equation 38 using an analog of equation 27 $$ (\mathfrak{m}^{-1})_{\gamma\epsilon,\alpha\beta}\mathfrak{m}^{\alpha\beta,\mu\nu}\mathfrak{A}_{\mu\nu}=\frac{1}{2}(\mathfrak{m}^{-1})_{\gamma\epsilon,\alpha\beta}(\partial_{\theta_i}\Sigma^{\alpha\beta})\\ \delta^\mu_\gamma\delta^\nu_\epsilon\mathfrak{A}_{\mu\nu}=\frac{1}{2}(\mathfrak{m}^{-1})_{\gamma\epsilon,\alpha\beta}(\partial_{\theta_i}\Sigma^{\alpha\beta})\\ \mathfrak{A}_{\gamma\epsilon}=\frac{1}{2}(\mathfrak{m}^{-1})_{\gamma\epsilon,\alpha\beta}(\partial_{\theta_i}\Sigma^{\alpha\beta}). $$

However, in going through the motions of calculating this inverse tensor for several of their examples (see section 4.1 for example), I keep running into issues where the method to calculate the inverse fails as the matrix is singular. Is there some other way of calculating the inverse (specifically of the singular "matrix") that I'm unaware of or is there a separate definition for taking the tensor inverse (I know that they are not usually unique)?

Below I list my methods for calculating the inverse, which typically work for a generic matrix with symbolic elements using mathematica. Neither of which yield an inverse of the tensor examples given in the text due to their singular nature.

  1. I used the code found in this post https://mathematica.stackexchange.com/questions/244973/inverse-of-the-matrix-with-several-indices

  2. solving for the inverse directly from the definition as a system of linear equations

numModes=4;
b = Table[
   Symbol["b" <> ToString[i] <> ToString[j] <> ToString[k] <> 
     ToString[l]], {i, 1, numModes}, {j, 1, numModes}, {k, 1, numModes}, {l, 1, numModes}];

Solve[And @@ 
   Flatten[
      Table[
         Sum[b[[i, j, l, k]]*M[[l, k, m, n]], {l, 1, numModes}, {k, 1, numModes}] 
             == KroneckerDelta[i, l]KroneckerDelta[j, p], 
       {i, 1, numModes}, {j, 1,numModes}, {m, 1, numModes}, {p, 1, numModes}]
    ], 
Flatten[b]]


This post imported from StackExchange Physics at 2024-10-19 20:42 (UTC), posted by SE-user ModeQuanta

asked Sep 24 in Theoretical Physics by ModeQuanta (5 points) [ revision history ]
edited Oct 19 by Dilaton
You probably want to use a regularization procedure (add a tiny bit of a state that is full rank, do the calculation, then take a limit where that parameter vanishes) arxiv.org/abs/1801.00299v4

This post imported from StackExchange Physics at 2024-10-19 20:42 (UTC), posted by SE-user Quantum Mechanic
@QuantumMechanic thanks for the reference! Indeed that was incredibly helpful. It seems like the vectorization procedure is fairly specific. So, even if my matrix inverse program worked on a general matrix, it may not work in any case. Still a bit surprised that the straight sum method didn't work, but in any case the vectorization seems to give me consistent results with the paper.

This post imported from StackExchange Physics at 2024-10-19 20:42 (UTC), posted by SE-user ModeQuanta

Your answer

Please use answers only to (at least partly) answer questions. To comment, discuss, or ask for clarification, leave a comment instead.
To mask links under text, please type your text, highlight it, and click the "link" button. You can then enter your link URL.
Please consult the FAQ for as to how to format your post.
This is the answer box; if you want to write a comment instead, please use the 'add comment' button.
Live preview (may slow down editor)   Preview
Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
If you are a human please identify the position of the character covered by the symbol $\varnothing$ in the following word:
p$\hbar$ysi$\varnothing$sOverflow
Then drag the red bullet below over the corresponding character of our banner. When you drop it there, the bullet changes to green (on slow internet connections after a few seconds).
Please complete the anti-spam verification




user contributions licensed under cc by-sa 3.0 with attribution required

Your rights
...